Question

我正在使用MySQL 5.5.16

我有以下查询，它本身就可以正常工作。

SELECT DISTINCT i.id, 
CASE WHEN e.date >  '2012-10-16'
THEN e.date
ELSE  '9999-99-99'
END AS date, 
CASE WHEN e.date >  '2012-10-16'
THEN time
ELSE  '99-99-99'
END AS time
FROM items AS i
LEFT JOIN expiration AS e ON ( e.item_id = i.id ) 
WHERE (
(
data >=  '2012-10-16'
AND e.valid=1
)
OR i.never_expires=1
)
AND i.valid=1
ORDER BY date ASC , time ASC 
LIMIT 0 , 10

但是，当我将其包含在更大的查询中时，我收到错误Column 'date' in where clause is ambiguous。以下是上述查询位于JOIN：

内的示例

SELECT i.id, i.title, i.never_expires, 
CASE WHEN e.date>  '2012-10-16'
THEN e.date
ELSE  '9999-99-99'
END AS date, 
CASE WHEN e.date >  '2012-10-16'
THEN e.time
ELSE  '99-99-99'
END AS time, i.item_price AS price
FROM items AS i
LEFT JOIN expiration AS e ON ( e.item_id = i.id )
JOIN (
  SELECT DISTINCT i.id, 
  CASE WHEN e.date >  '2012-10-16'
  THEN e.date
  ELSE  '9999-99-99'
  END AS date, 
  CASE WHEN e.date >  '2012-10-16'
  THEN time
  ELSE  '99-99-99'
  END AS time
  FROM items AS i
  LEFT JOIN expiration AS e ON ( e.item_id = i.id ) 
  WHERE (
  (
  data>=  '2012-10-16'
  AND e.valid=1
  )
  OR i.never_expires=1
  )
  AND i.valid=1
  ORDER BY date ASC , time ASC 
  LIMIT 0 , 10
) AS ilist ON (i.id=ilist.id) 
WHERE (
(
date >=  '2012-10-16'
AND e.valid=1
)
OR i.never_expires=1
)
AND i.valid=1
ORDER BY dateASC , time ASC

为什么声称date含糊不清？

PS 我尝试使用date替换内部查询的AS date部分中的inner_date，但这只会引发另一个错误Unknown column 'inner_date' in 'where clause' ...

Answer 1

您正在将expiration表（名为date的列）加入到物化表中，该表本身有一个名为CASE的列（来自date表达式）。您应该使用date子句中的WHERE限定使用您想要引用的表的别名。

或者：

WHERE (
(
ilist.date >=  '2012-10-16'
AND e.valid=1
)

或者：

WHERE (
(
e.date >=  '2012-10-16'
AND e.valid=1
)

为什么在“JOIN（SELECT）”语句中使用别名会导致错误？

1 个答案: