Question

我使用的代码：

import xmppy
jid = xmpp.JID('user@gmail.com')
cl = xmpp.Client(jid.getDomain())
cl.connect(server=('talk.google.com',5222))
cl.auth('user@gmail.com', 'password','something')

它似乎一直在工作直到连接，我得到'tls'作为连接的回报。之后，cl.auth失败。我尝试使用有和没有@ gmail.com的用户名。我尝试过不同的用户，所以我的密码没错。我尝试使用5223而不是5222，在这种情况下我得到'ssl'作为回报。

以下是我得到的调试输出：

DEBUG: socket       got   <stream:stream from="gmail.com" id="960A4092BC8F9722" version="1.0" xmlns:stream="http://etherx.jabber.org/streams" xmlns="jabber:client">
  <stream:features>
  <mechanisms xmlns="urn:ietf:params:xml:ns:xmpp-sasl">
  <mechanism>PLAIN</mechanism>
  <mechanism>X-GOOGLE-TOKEN</mechanism>
  <mechanism>X-OAUTH2</mechanism>
  </mechanisms>
  </stream:features>
DEBUG: dispatcher   warn  Unknown stanza: features
DEBUG: dispatcher   ok    Dispatching unknown stanza with type-> props->[u'urn:ietf:params:xml:ns:xmpp-sasl'] id->None
DEBUG: sasl         start Plugging <xmpp.auth.SASL instance at 0x2f22998> into <xmpp.client.Client instance at 0x2f19bd8>
DEBUG: dispatcher   info  Registering handler <bound method SASL.SASLHandler of <xmpp.auth.SASL instance at 0x2f22998>> for "challenge" type-> ns->(urn:ietf:params:xml:ns:xmpp-sasl)
DEBUG: dispatcher   warn  Registering namespace "urn:ietf:params:xml:ns:xmpp-sasl"
DEBUG: dispatcher   info  Registering protocol "unknown" as <class 'xmpp.protocol.Protocol'>(urn:ietf:params:xml:ns:xmpp-sasl)
DEBUG: dispatcher   info  Registering protocol "default" as <class 'xmpp.protocol.Protocol'>(urn:ietf:params:xml:ns:xmpp-sasl)
DEBUG: dispatcher   warn  Registering protocol "challenge" as <class 'xmpp.protocol.Protocol'>(urn:ietf:params:xml:ns:xmpp-sasl)
DEBUG: dispatcher   info  Registering handler <bound method SASL.SASLHandler of <xmpp.auth.SASL instance at 0x2f22998>> for "failure" type-> ns->(urn:ietf:params:xml:ns:xmpp-sasl)
DEBUG: dispatcher   warn  Registering protocol "failure" as <class 'xmpp.protocol.Protocol'>(urn:ietf:params:xml:ns:xmpp-sasl)
DEBUG: dispatcher   info  Registering handler <bound method SASL.SASLHandler of <xmpp.auth.SASL instance at 0x2f22998>> for "success" type-> ns->(urn:ietf:params:xml:ns:xmpp-sasl)
DEBUG: dispatcher   warn  Registering protocol "success" as <class 'xmpp.protocol.Protocol'>(urn:ietf:params:xml:ns:xmpp-sasl)
DEBUG: socket       sent  <auth xmlns="urn:ietf:params:xml:ns:xmpp-sasl" mechanism="PLAIN">Y3MxMGIwNTlAZ21haWwuY29tQGdtYWlsLmNvbQBjczEwYjA1OUBnbWFpbC5jb20AcHZ6bXZoN3FjYzE=</auth>
DEBUG: socket       error Socket error while receiving data
Traceback (most recent call last):
  File "/usr/local/lib/python2.7/dist-packages/xmpppy-0.5.0rc1-py2.7.egg/xmpp/transports.py", line 153, in receive
    try: received = self._recv(BUFLEN)
SSLError: [Errno 8] _ssl.c:1359: EOF occurred in violation of protocol
DEBUG: client       stop  Disconnect detected
DEBUG: socket       error Socket operation failed
DEBUG: sasl         stop  Plugging <xmpp.auth.SASL instance at 0x2f22998> out of <xmpp.client.Client instance at 0x2f19bd8>.

Answer 1

解决了这个问题，这是最愚蠢的事情。 Gmail阻止访问，因为它认为我的应用活动“可疑且不寻常” 我必须从浏览器登录我的帐户，告诉他们这是我，然后在10分钟内从应用程序登录

Answer 2

由于某些奇怪的原因（对于某些用户）仅适用于域googlemail.com。也许你想尝试这个。所以你的用户名没有@或任何域名，服务器是googlemail.com

我正在尝试使用xmpppy连接到gtalk。我如何进行身份验证？我在许多地方找到的简单代码无效

2 个答案: