NSURL *URL = [NSURL URLWithString:@"http://"];
NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:URL];
request.HTTPMethod = @"POST";
NSString *params = @"json=deepak";
NSData *data = [params dataUsingEncoding:NSUTF8StringEncoding];
[request addValue:@"8bit" forHTTPHeaderField:@"Content-Transfer-Encoding"];
[request addValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"];
[request addValue:[NSString stringWithFormat:@"%i", [data length]] forHTTPHeaderField:@"Content-Length"];
[request setHTTPBody:data];
NSURLResponse *responce;
NSError *error;
NSData *returnData = [ NSURLConnection sendSynchronousRequest:request returningResponse:&responce error:&error];
NSString *content = [NSString stringWithUTF8String:[returnData bytes]];
NSLog(@"responseData: %@", content);
大家好,我正在使用stackOverflow本身的代码并且编写的答案正在运行,但我得到了
来自php服务器的“response data = null”
我的简单服务器代码是
$ json = CJSON :: decode($ _ POST ['json'],TRUE); echo CJSON :: encode($ json);
答案 0 :(得分:0)
是的,我终于解决了我的问题..... 为了使密钥对值,我必须以数组方式发送数据。即
@"{\"user\":\"deepak\",\"password\":\"1234\"}";
这是json键的值。
然后你可以使用
在php服务器上解码$ json = CJSON :: decode($ _ POST ['json'],TRUE); echo CJSON :: encode($ json);
就像这样,它就像魅力一样