Question

由于我的其他问题已经关闭，这里是必需的数据。我要做的是让R计算列城的最后一列'计数'，这样我就可以映射数据了。因此，我需要某种代码来匹配这一点。因为我想显示有多少参与者（计数）处于例如夏威夷（HI）状态

zip     city         state  latitude    longitude   count
96860   Pearl Harbor    HI  24.859832   -168.021815 36
96863   Kaneohe Bay     HI  21.439867   -157.74772  39
99501   Anchorage       AK  61.216799   -149.87828  12
99502   Anchorage       AK  61.153693   -149.95932  17
99506   Elmendorf AFB   AK  61.224384   -149.77461  2

我尝试过的是

match<- c(match(datazip$state, datazip$number))>$

但是我真的很无奈试图寻找解决方案，因为我甚至不知道如何描述这个。我之后的计划是用数据制作等值线图并相信我，现在我已经看到了几乎所有尝试提供建议的页面。所以你的帮助非常感谢。感谢

Answer 1

# I read your sample data to a data frame
> df
    zip          city state latitude longitude count
1 96860  Pearl_Harbor    HI 24.85983 -168.0218    36
2 96863   Kaneohe_Bay    HI 21.43987 -157.7477    39
3 99501     Anchorage    AK 61.21680 -149.8783    12
4 99502     Anchorage    AK 61.15369 -149.9593    17
5 99506 Elmendorf_AFB    AK 61.22438 -149.7746     2

# If you want to sum the number of counts by state
library(plyr)
> ddply(df, .(state), transform, count2 = sum(count))
    zip          city state latitude longitude count count2
1 99501     Anchorage    AK 61.21680 -149.8783    12     31
2 99502     Anchorage    AK 61.15369 -149.9593    17     31
3 99506 Elmendorf_AFB    AK 61.22438 -149.7746     2     31
4 96860  Pearl_Harbor    HI 24.85983 -168.0218    36     75
5 96863   Kaneohe_Bay    HI 21.43987 -157.7477    39     75

Answer 2

也许aggregate对您来说是一个很好而简单的解决方案：

df
    zip          city state latitude longitude count
1 96860  Pearl Harbor    HI 24.85983 -168.0218    36
2 96863   Kaneohe Bay    HI 21.43987 -157.7477    39
3 99501     Anchorage    AK 61.21680 -149.8783    12
4 99502     Anchorage    AK 61.15369 -149.9593    17
5 99506 Elmendorf AFB    AK 61.22438 -149.7746     2

aggregate(df$count,by=list(df$state),sum)
  Group.1  x
1      AK 31
2      HI 75

aggregate(df$count,by=list(df$city),sum)
        Group.1  x
1     Anchorage 29
2 Elmendorf AFB  2
3   Kaneohe Bay 39
4  Pearl Harbor 36

计算具有相同标题的行

2 个答案: