“失踪”“错误

Question

我正在编写询问用户姓名和年龄的代码。

var name;
var age;

name = prompt("What is your name?");
age = prompt("What is your age?");

代码设置为重复他们的姓名和年龄，然后使用if语句向他们发送一条消息，说明“你年轻”，如果年龄变量低于50岁。

但是，我有一个问题。我无法打印告诉用户他们输入的年龄和姓名的字符串。我收到一个语法错误，告诉我有一个意外的字符串。

问题代码是：

console.log("You're name is " +name " and you are " +age "years old.");

如果我只将一个变量打印到控制台，代码工作正常，如下所示：

console.log("You're name is " +name.);

希望你们能帮助我。

完整代码：

var name;
var age;

name = prompt("What is your name?");
age = prompt("What is your age?");

console.log("You're name is " +name " and you are " +age "years old.")

var printNameAndAge = function() {
    if (age>50) {
        console.log("Dang you're old.");
    }
    else {
        console.log("You're pretty young, "+name);
        alert("You're pretty young, "+name);
    }
};

printNameAndAge();

Answer 1

console.log("Your name is " + name + " and you are " + age + " years old.");

要插入变量内联，您需要在和之后使用连接运算符。

Answer 2

+之后你遗失了两个name，age之后遗漏了一个console.log("You're name is " +name + " and you are " +age+ "years old."); 。请更正如下：

{{1}}

Answer 3

你忘记了一些优点！

console.log("You're name is " +name " and you are " +age "years old.");

应该是

console.log("You're name is " +name +" and you are " +age+ "years old.");