Question

发布查询检索所有相关字段，但 SUM(af_py_commission) 函数导致问题，并且只是在结尾处添加额外的零，然后在右端添加。

e.g。如果答案是45，它将给出450并且该字段的数据格式是浮动的，否则这个查询工作正常....

我尝试在同一个字段上使用相同功能的简单查询，但没有连接，所以它工作正常并给出正确的ans。任何人都可以帮助我在这个＆gt; ??

中做错了

SELECT f.af_id AS af_if
   , aff_cust_tbl.af_id AS cu_af_id
   , aff_payment_tbl.af_cust_id AS pym_cus_id
   , SUM(af_py_commission)
FROM aff_tbl AS f
INNER JOIN aff_tbl ON f.af_id = 2
INNER JOIN aff_cust_tbl ON aff_cust_tbl.af_id = 2
INNER JOIN aff_payment_tbl ON aff_payment_tbl.af_id = 2;

Answer 1

内连接错误

试试这个：

SELECT
f.af_id                    AS af_if,
aff_cust_tbl.af_id         AS cu_af_id,
aff_payment_tbl.af_cust_id AS pym_cus_id,
SUM(af_py_commission)
FROM aff_tbl AS f
INNER JOIN aff_tbl as f2
ON f.af_id = 2 AND f2.af_id=2
INNER JOIN aff_cust_tbl
ON aff_cust_tbl.af_id = 2
INNER JOIN aff_payment_tbl
ON aff_payment_tbl.af_id = 2;

编辑的行是

 INNER JOIN aff_tbl as f2
 ON f.af_id = 2 AND f2.af_id=2

试试这个：

SELECT f.af_id                    AS af_if, 
       aff_cust_tbl.af_id         AS cu_af_id, 
       aff_payment_tbl.af_cust_id AS pym_cus_id, 
       Sum(af_py_commission) 
FROM   aff_tbl AS f 
       INNER JOIN aff_cust_tbl 
               ON f.af_id = aff_cust_tbl.af_id 
       INNER JOIN aff_payment_tbl 
               ON aff_payment_tbl.af_id = aff_cust_tbl.af_id 
WHERE  f.af_id = 2;

如果它没有给出正确的结果，请尝试在此处进行总结和后期分析......

Answer 2

如果使用聚合函数，可能缺少GROUP BY子句。试试这个：

SELECT
f.af_id                    AS af_if,
aff_cust_tbl.af_id         AS cu_af_id,
aff_payment_tbl.af_cust_id AS pym_cus_id,
SUM(af_py_commission)
FROM aff_tbl AS f
INNER JOIN aff_tbl
ON f.af_id = 2
INNER JOIN aff_cust_tbl
ON aff_cust_tbl.af_id = 2
INNER JOIN aff_payment_tbl
ON aff_payment_tbl.af_id = 2;
GROUP BY f.af_id

查询多个连接和求和函数给出错误的总数或总和

2 个答案: