Question

private void insertIntoMyTable (Myclass m) {
    String query = "INSERT INTO MYTABLE (NAME) VALUES (?)";
    jdbcTemplate.update(query, m.getName());
}

当上述查询插入记录时，表中的ID列会自动增量。

有没有办法在插入时获取此自动递增的ID。因此，在此示例中，my方法的返回值为int

Answer 1

检查this reference.您可以将jdbcTemplate.update用作：

修改按要求添加了进口

import java.sql.Connection; import java.sql.PreparedStatement; import java.sql.SQLException; import org.springframework.jdbc.core.JdbcTemplate; import org.springframework.jdbc.core.PreparedStatementCreator; import org.springframework.jdbc.support.GeneratedKeyHolder; import org.springframework.jdbc.support.KeyHolder;

以下是代码用法：

final String INSERT_SQL = "insert into my_test (name) values(?)"; final String name = "Rob"; KeyHolder keyHolder = new GeneratedKeyHolder(); jdbcTemplate.update( new PreparedStatementCreator() { public PreparedStatement createPreparedStatement(Connection connection) throws SQLException { PreparedStatement ps = connection.prepareStatement(INSERT_SQL, new String[] {"id"}); ps.setString(1, name); return ps; } }, keyHolder); // keyHolder.getKey() now contains the generated key

Answer 2

我在下面插入后得到数据库（MSSQL）生成的id，导入：

  import org.springframework.jdbc.core.BeanPropertyRowMapper;
  import org.springframework.jdbc.core.JdbcTemplate;
  import org.springframework.jdbc.core.RowMapper;
  import org.springframework.jdbc.core.SqlParameter;
  import org.springframework.jdbc.core.SqlReturnResultSet;
  import org.springframework.jdbc.core.simple.SimpleJdbcCall;

和代码段：

    final String INSERT_SQL = "INSERT INTO [table]\n"
            + " ([column_1]\n"
            + " ,[column_2])\n"
            + " VALUES\n" +
            " (?, ?)";

    Connection connection = jdbcTemplate.getDataSource().getConnection();
    PreparedStatement preparedStatement = connection.prepareStatement(INSERT_INVOICE_SQL, Statement.RETURN_GENERATED_KEYS);
    preparedStatement.setString(1, "test 1");
    preparedStatement.setString(2, "test 2");

    preparedStatement.executeUpdate();
    ResultSet keys = preparedStatement.getGeneratedKeys();

    if (keys.next()) {
        Integer generatedId = keys.getInt(1); //id returned after insert execution
    }

Answer 3

@Component
public class PersonDao {

    private final JdbcTemplate jdbcTemplate;

    @Autowired
    public PersonDao(JdbcTemplate jdbcTemplate) {
        this.jdbcTemplate = jdbcTemplate;
    }

    public List<Person> index() {
        return jdbcTemplate.query("SELECT * FROM person", new BeanPropertyRowMapper<>(Person.class));
    }

    public Person show(int id){
        return jdbcTemplate.query("SELECT * FROM person WHERE id=?", new Object[]{id}, new BeanPropertyRowMapper<>(Person.class))
                .stream().findAny().orElse(null);
    }

    public void save(Person person){
        jdbcTemplate.update("INSERT INTO person (name, age, email) VALUES (?, ?, ?)", person.getName(), person.getAge(), person.getEmail());
    }

    public void edit(Integer id, Person person) {
        jdbcTemplate.update("UPDATE person SET name = ?, age = ?, email = ? WHERE id = ?", person.getName(), person.getAge(), person.getEmail(), id);
    }

    public void delete(Integer id) {
        jdbcTemplate.update("DELETE FROM person WHERE id = ?", id);
    }
}

Answer 4

JdbcTemplate是Spring的核心。另一种选择是使用SimpleJdbcInsert。

SimpleJdbcInsert simpleJdbcInsert = new SimpleJdbcInsert(jdbcTemplate);
simpleJdbcInsert
    .withTableName("TABLENAME")
    .usingGeneratedKeyColumns("ID");
SqlParameterSource params = new MapSqlParameterSource()
    .addValue("COL1", model.getCol1())
    .addValue("COL2", model.getCol2());
Number number = simpleJdbcInsert.executeAndReturnKey(params);

你仍然可以@Autowire jdbcTemplate。对我来说，这比使用jdbcTemplate.update（）方法和KeyHolder获取实际id更方便。

示例代码段使用Apache Derby进行测试，并且应该与常用数据库一起使用。

使用Spring JPA是另一种选择 - 如果ORM适合您。

当我通过jdbctemplate在表中插入记录时，如何获取自动增量ID

4 个答案: