Question

我得到了这个问题，我试了好几次，没有想到任何事情:(

这是一个问题：设计并编写一个程序来输入10个人的权重。它应该只接受20公斤到100公斤之间的重量。你的程序应该计算并打印这些人的平均，最大和最小权重。

这是我试过的代码。任何人都可以完成这个或提出简化的代码吗？这是正确的，我的意思是我这样做的方式？请帮忙

import java.util.Scanner;

class WeightOfPeople{
public static void main(String args []){

    Scanner sc = new Scanner(System.in);
    System.out.print("Enter a weight between 20kg - 100kg :");
    int weight1 = sc.nextInt();


    if(20 < weight1 && weight1 < 100){
            System.out.print("Enter a weight between 20kg - 100kg :");
            int weight2 = sc.nextInt();             
    }else{
        System.out.println("Enter a correct weight");
    }           
}

Answer 1

试试这个：

Scanner sc = new Scanner(System.in);
int count = 0;
int total = 0;
int min = 101;
int max = 19;
while(count < 3) {
    System.out.print("Enter a weight between 20kg - 100kg :");
    int nextWeight = sc.nextInt();
    if(20 <= nextWeight && nextWeight <= 100){
        total += nextWeight;
        if(nextWeight < min) {
            min = nextWeight;
        }
        if(nextWeight > min) {
            max = nextWeight;
        }
        count++;
    }
    else{
        System.out.println("Enter a correct weight");
    }
}
System.out.println("Average = " + ((double)total/count));
System.out.println("Min = " + min);
System.out.println("Max = " + max);

Answer 2

您希望用户能够输入 10个不同的值。因此，您需要某种循环。

e.g。

for (int i = 0 ; i < 10 ; i++) {
    System.out.print("Enter a weight: ");
    // record users input
}

我要做的是维护一个整数数组来存储用户输入的所有数据。收集数据后，您可以循环此数组以确定最小值，最大值和平均值。像这样：

int min = weights[0];
int max = weights[0];
double avg = 0;

for (int weight : weights) {
    if (weight < min)
        min = weight;
    if (weight > max)
        max = weight;
    avg += weight;
}

avg /= weights.length;

总的来说，你会有这样的事情：

Scanner in = new Scanner(System.in);
int[] weights = new int[10];
for (int i = 0 ; i < 10 ; i++) {
    System.out.print("Enter a weight between 20 and 100: ");
    weights[i] = in.nextInt();
}
in.close();

int min = weights[0];
int max = weights[0];
double avg = 0;

for (int weight : weights) {
    if (weight < min)
        min = weight;
    if (weight > max)
        max = weight;
    avg += weight;
}

avg /= weights.length;

System.out.println("Min: " + min);
System.out.println("Max: " + max);
System.out.println("Average: " + avg);

Answer 3

public static void main(String args []){
  Scanner sc = new Scanner(System.in);
  int i = 0;
  int sum = 0;
  int min = Integer.MAX_VALUE;
  int max = Integer.MIN_VALUE; 
  do{
    System.out.print("Enter a weight between 20kg - 100kg :");
    int weight = sc.nextInt();
    if(20 <= weight && weight <= 100){
      sum += weight;
      if(weight<min){
        min = weight;
      }
      if(weight>max){
        max = weight;
      }
      i++;
    }
    else {
      System.out.println("Enter a correct weight");
    }
  } while(i<=10)
  System.out.println("AVG "+ (sum/10)+" Min "+ min +" Max "+max);
}

家庭作业：平均10个用户输入的数字

3 个答案: