如何获取函数中的默认构造函数值

Question

AppXmlLogWritter objParameterized = new AppXmlLogWritter(1234, "LogApplication", "LogFilepath");

AppXmlLogWritter objParmeterlessConstr = new AppXmlLogWritter();

objParameterized.WriteXmlLog("0", "LogFlag");

如何在此函数中获取默认构造函数值？

Answer 1

通过this（）

在你的其他构造函数中调用构造函数，如下所示

    public AppXmlLogWritter(int intLogIDPrefix, string strLogApplication, string strLogFilePath)
          :this()
    {
        LogIDPrefix = intLogIDPrefix;
        LogApplication = strLogApplication;
        LogFilePath = strLogFilePath;
    }

Answer 2

要从另一个构造函数调用类的基础构造函数，请使用this关键字，如下所示：

public AppXmlLogWritter(int intLogIDPrefix, string strLogApplication, string strLogFilePath) 
    : this()
{ ... }

Answer 3

不太清楚你在谈论什么价值，但是如果你引用randomNumber，你已经在类中找到了它。

如果您要调用的函数是使用类型AppXmlLogWritter的函数，则可以定义如下属性：

public class AppXmlLogWritter{


        public int RandomNumber {get;set}; //PUBLIC PROPERTY


        public AppXmlLogWritter()
        {
            Random random = new Random();
            RandomNumber = random.Next(9999);
            LogDateTime = DateTime.Now.ToString("yyyyMMdd HHmmss");
        }

     .... ..
     .... ..       

}