如何在C#.net中的变量中保存SQL查询的结果?

时间:2012-10-13 18:03:54

标签: c# sql

namespace Hotel
{
    public partial class Billing : Form
    {
        SqlConnection con = new SqlConnection();
        SqlDataAdapter da;
        SqlCommand cmd = new SqlCommand();
        DataTable dt = new DataTable();
        public Billing()
        {
            InitializeComponent();
        }

        private void Billing_Load(object sender, EventArgs e)
        {
            con.ConnectionString = "Data Source=.\\SQLEXPRESS;AttachDbFilename=D:\\Projects\\c# assignments\\Hotel Manager\\Hotel\\database\\master.mdf;Integrated Security=True;User Instance=True";
            //loadData();
        }

        private void button1_Click(object sender, EventArgs e)
        {
            con.Open();
            int rno = Int32.Parse(txtRoom.Text);


            cmd.CommandText = "SELECT SUM(ItemRate) FROM logs WHERE RoomNo=" + rno +"";
            int amt = (int)cmd.ExecuteScalar();   //arror is at this part

       //ExecuteScalar: Connection property has not been initialized.

            cmd.CommandText = "INSERT INTO bill VALUES('" + txtBillNo.Text.ToString() + "','" + txtRoom.Text.ToString() + "','" + amt.ToString() + "')";
            con.Close();
            txtBillNo.Text = "";
            txtRoom.Text = "";
            BillView bv = new BillView();
            bv.ShowDialog();
        }
    }
}

请帮我解决这个错误我无法将SQL查询结果存储到变量???

7 个答案:

答案 0 :(得分:10)

  1. 您对SQL-Injection持开放态度。不要连接字符串来构建查询。而是使用SQL参数。
  2. 使用using-statement进行连接(以及实施IDisposable的所有其他内容)。 Dispose也将关闭连接,即使出错也会using
  3. 异常的原因是您没有初始化SqlCommand的连接,因为您没有指定连接。您可以使用property或相应的constructor
  4. 以下是一个例子:

    int amt;  
    using (var con = new SqlConnection(ConnectionString)) {
        var sql = "SELECT SUM(ItemRate) FROM logs WHERE RoomNo = @RoomNo";
        using (var cmd = new SqlCommand(sql, con)) {
            cmd.Parameters.AddWithValue("@RoomNo", Int32.Parse(txtRoom.Text));
            con.Open();
            amt = (int)cmd.ExecuteScalar();
        }
    }
    

答案 1 :(得分:1)

打开连接是不够的;
您需要将concmd相关联。

答案 2 :(得分:1)

与所描述的错误完全相同,您尚未设置SQLCommand的{​​{3}}属性。

尝试添加:

cmd.Connection = con;
在致电ExecuteScalar()之前

答案 3 :(得分:1)

您已经打开了一个SqlConnection,但是您还没有告诉SqlCommand对象使用它。尝试添加以下行:

cmd.Connection = con;

在执行查询之前。

答案 4 :(得分:1)

您展示的代码存在一些问题 - 尤其是一些seroius安全问题,我强烈建议您阅读SQL injection并准备好语句/参数和using

只是一些快速更正/评论:

namespace Hotel
{
    public partial class Billing : Form
    {
        SqlConnection con = new SqlConnection();
        SqlDataAdapter da;
        SqlCommand cmd = new SqlCommand();
        DataTable dt = new DataTable();
        public Billing()
        {
            InitializeComponent();
        }

        private void Billing_Load(object sender, EventArgs e)
        {
            con.ConnectionString = "Data Source=.\\SQLEXPRESS;AttachDbFilename=D:\\Projects\\c# assignments\\Hotel Manager\\Hotel\\database\\master.mdf;Integrated Security=True;User Instance=True";
            //loadData();
        }

        private void button1_Click(object sender, EventArgs e)
        {
            con.ConnectionString = "Data Source=.\\SQLEXPRESS;AttachDbFilename=D:\\Projects\\c# assignments\\Hotel Manager\\Hotel\\database\\master.mdf;Integrated Security=True;User Instance=True";
            con.Open();
            int rno = Int32.Parse(txtRoom.Text);

            cmd.Connection = con; // This solves the problem you see
            // HERE you SHOULD use a SQL paramter instead of appending strings to build your SQL !!!
            cmd.CommandText = "SELECT SUM(ItemRate) FROM logs WHERE RoomNo=" + rno +"";
            int amt = (int)cmd.ExecuteScalar();   //arror is at this part


            // HERE you SHOULD use a SQL paramter instead of appending strings to build your SQL !!!
            // Another point: you build an INSERT but never execute it ?!?
            cmd.CommandText = "INSERT INTO bill VALUES('" + txtBillNo.Text.ToString() + "','" + txtRoom.Text.ToString() + "','" + amt.ToString() + "')";
            con.Close();
            txtBillNo.Text = "";
            txtRoom.Text = "";
            BillView bv = new BillView();
            bv.ShowDialog();
        }
    }
}

答案 5 :(得分:1)

您没有在button1_click中提供连接字符串。

con.ConnectionString = "Data Source=.\\SQLEXPRESS;AttachDbFilename=D:\\Projects\\c# assignments\\Hotel Manager\\Hotel\\database\\master.mdf;Integrated Security=True;User Instance=True";

你的代码中还有很多问题。它以这种方式工作

{
  // Create Connection Object  
  // Provide connection object with Connection string
  // Create command object
  // Open connection
  // Execute command
  // Close connection
  // Dispose connection
}

答案 6 :(得分:0)

using (SqlConnection sqlcon = new SqlConnection("Connection String HERE"))
        {
            using (SqlCommand sqlcmd= new SqlCommand())
            {
                sqlcmd.Connection = sqlcon;            
                sqlcmd.CommandType = CommandType.Text;
                sqlcmd.CommandText = "SELECT SUM(ItemRate) FROM logs WHERE RoomNo=@rno";
                slqcmd.Parameters.AddWithValue("@rno", rno);
                try
                {
                    sqlcon.Open();
                    command.ExecuteNonQuery();
                }
                catch (SqlException)
                {
                    MessageBox.Show("Your Error Here");
                }
                finally
                {
                    connection.Close();
                }
            }

我认为这会有所帮助,而且更安全