Question

bash中的have是关键字吗？或者bash完成脚本使用的语言不是bash？

have gcc &&
_gcc()
{

很常见。请参阅：grep "have .* &&" /etc/bash_completion.d/*

我找不到有关我看过的bash完成教程的任何信息，但在man bash中找不到任何信息。它也很难谷歌＆＃34;有＆＃34;。我在哪里可以找到关于此的文档？

我猜测它与确保gcc中存在PATH有关吗？

编辑：是的。 /etc/bash_completion包含：

have()
{
    unset -v have
    # Completions for system administrator commands are installed as well in
    # case completion is attempted via `sudo command ...'.
    PATH=$PATH:/sbin:/usr/sbin:/usr/local/sbin type $1 &>/dev/null &&
    have="yes"
}

Answer 1

have和_have只是基本bash_completion文件中定义的两个函数。在两者之间，它们形成了内置type命令的包装器，以确定特定的命令/程序是否可用。

# This function checks whether we have a given program on the system.
#
_have()
{
    # Completions for system administrator commands are installed as well in
    # case completion is attempted via `sudo command ...'.
    PATH=$PATH:/usr/sbin:/sbin:/usr/local/sbin type $1 &>/dev/null
}

# Backwards compatibility for compat completions that use have().
# @deprecated should no longer be used; generally not needed with dynamically
#             loaded completions, and _have is suitable for runtime use.
have()
{
    unset -v have
    _have $1 && have=yes
}

bash完成的'have'关键字

1 个答案: