Question

我想创建一个运行队列中所有作业的方法（作业列表）。我创建了一个运行一个作业的方法（runAJob），而下面的方法是运行队列列表中的所有作业，直到时间（myTimeLeft）用完为止。
现在，当我运行runAll方法时，此代码总是会留下1个ArraLyist。有人会告诉我为什么这是错的吗？

   /**
  * Run the first job on the queue if there is enough time on the clock and the job queue list is not empty.
  * And move the job to the finished jobs list.
  */
public void runAJob(){
   myJobDuration = myJobInQueue.get(0).getDuration();
   if(!myJobInQueue.isEmpty())
   {
        if (myJobDuration < myTimeLeft)
        {
            myTimeLeft = myTimeLeft - myJobDuration;
            myFinishedJobs.add(myJobInQueue.get(0));
            System.out.println("A job is running: " + myJobInQueue.get(0).getName());
            myJobInQueue.remove(0);
        }
        else 
        {
            System.out.println("Not enogth running time left, please add time on the clock.");             
        }
   }
   else 
   {
     System.out.println("No pending job on the list.");
   }
}

/**
  * Run all the jobs on the queue in order until it runs out of time.
  */  
public void runAll()
{
  int counAJob =0; 
  while (myJobDuration < myTimeLeft && !myJobInQueue.isEmpty()) {
   // get next item from queue
     runAJob();
     System.out.println("A job is running: ");
  }

}

Answer 1

为什么你（大概）使用队列时有for循环？您不会根据队列的大小（i）做出任何决定。我会坚持让Queue处理自己：

// declarations and definitions

while (myJobDuration < myTimeLeft && !myJobInQueue.isEmpty()) {
    // get next item from queue
    runAJob();
}

如何在队列基本循环中打印String

1 个答案: