当模型表单中有多个字段时,文件不会上传

时间:2012-10-13 12:45:26

标签: python django filefield

如果我的模型中有多个字段而不是文件字段,则无法上传文件。我没有在页面上收到任何错误,但页面只是显示相同的页面而没有上传我的图像。

这是我的模特

class ImageUpload(models.Model):
   username = models.ForeignKey(User)
   imagefile = models.FileField(upload_to='pictures')
   isapproved = models.BooleanField()
   class Meta:
       db_table = u'imageupload'

   def __unicode__(self):
       return u'%s' % (self.imagefile)

这是我的模型表格

class UploadImageForm(forms.ModelForm):
   def __init__(self,user, *args, **kwargs):
       super(UploadImageForm, self).__init__(*args, **kwargs)
       self.fields['username'] = forms.CharField(initial = user,
                                       widget = forms.TextInput(
                                     attrs = {'readonly':'readonly'}))
   class Meta:
       model = ImageUpload
       exclude = ('id', 'isapproved')

以下是我处理数据的地方。

def imageupload(request):
# Handle file upload
   if request.method == 'POST':
      list = ["jpeg", "jpg","JPG","JPEG","png","PNG"]
      format = imghdr.what(request.FILES['imagefile'])
      if format not in list:
          error = "Please upload a valid file format"
          form = UploadImageForm(request.user)
          return HttpResponseRedirect(reverse('myview.views.imageupload'))
      else:
          form = UploadImageForm(request.POST, request.FILES)
          if form.is_valid():
              newdoc = ImageUpload(imagefile = request.FILES['imagefile'])
              newdoc.save()
          return HttpResponseRedirect(reverse('myview.views.imageupload'))
  else:
      form = UploadImageForm(request.user) # A empty, unbound form
  documents = ImageUpload.objects.all()
  return render_to_response('imageupload.html',
       {'documents': documents, 'form': form,'media':settings.MEDIA_URL},
        context_instance=RequestContext(request)
   )

当我在模型表单中仅使用文件字段时,它曾经正常工作。向模型添加更多字段后,不上传文件。关于如何解决这个问题的任何建议?

提前致谢 Vikram

1 个答案:

答案 0 :(得分:1)

只需在视图中添加一个else块即可进行表单验证。我认为您的表单无效,并且您不只是在模板中打印任何错误。

if form.is_valid():
    newdoc = ImageUpload(imagefile = request.FILES['imagefile'])
    newdoc.save()
else:
    # do something visible here

此外,如果您的表单有效,则可以使用form.save()保存图片和相关数据,而不是创建新的ImageUpload对象。

此外,您的模型需要保存User对象。