从android上传文件加字符串到服务器不起作用

时间:2012-10-13 08:42:18

标签: php android file upload webserver

我想使用php将文件从android设备上传到服务器。另外,我想将文件的名称发送到带有WHERE语句的数据库。我可以上传我的文件,但我无法发送WHERE语句,我不知道在何处以及如何将它放在android源代码中。

这是我的PHP代码:

<form action="FileUp.php" method="post" enctype="multipart/form-data">
</form>

<?php

mysql_connect('localhost','root','root');
mysql_select_db('db');

$target_path  = "./";
$target_path = $target_path . basename( $_FILES['uploadedfile']['name']);
$file = basename( $_FILES['uploadedfile']['name']);
if(move_uploaded_file($_FILES['uploadedfile']['tmp_name'], $target_path)){
echo "The file ".  basename( $_FILES['uploadedfile']['name']).
" has been uploaded";
} else{
echo "There was an error uploading the file, please try again!";
}
$ident=addslashes($_POST['ident']);

mysql_query ("UPDATE table SET column = CONCAT(column,'$file') WHERE id = '$ident'");

?>

这是java代码:

@Override
        public void onClick(View v) {
            // TODO Auto-generated method stub

            String exsistingFileName = file.getText().toString();
            String lineEnd = "\r\n";
            String twoHyphens = "--";
            String boundary = "*****";
            try {
                // ------------------ CLIENT REQUEST

                Log.e(Tag, "Inside second Method");

                FileInputStream fileInputStream = new FileInputStream(new File(
                        exsistingFileName));

                // open a URL connection to the Servlet

                URL url = new URL(urlString);

                // Open a HTTP connection to the URL

                conn = (HttpURLConnection) url.openConnection();

                // Allow Inputs
                conn.setDoInput(true);

                // Allow Outputs
                conn.setDoOutput(true);

                // Don't use a cached copy.
                conn.setUseCaches(false);

                // Use a post method.
                conn.setRequestMethod("POST");

                conn.setRequestProperty("Connection", "Keep-Alive");

                conn.setRequestProperty("Content-Type",
                        "multipart/form-data;boundary=" + boundary);

                DataOutputStream dos = new DataOutputStream(conn.getOutputStream());

                dos.writeBytes(twoHyphens + boundary + lineEnd);
                dos
                        .writeBytes("Content-Disposition: post-data; name=uploadedfile;filename="
                                + exsistingFileName + "" + lineEnd);
                dos.writeBytes(lineEnd);

                Log.e(Tag, "Headers are written");

                // create a buffer of maximum size

                int bytesAvailable = fileInputStream.available();
                int maxBufferSize = 1000;
                // int bufferSize = Math.min(bytesAvailable, maxBufferSize);
                byte[] buffer = new byte[bytesAvailable];

                // read file and write it into form...

                int bytesRead = fileInputStream.read(buffer, 0, bytesAvailable);

                while (bytesRead > 0) {
                    dos.write(buffer, 0, bytesAvailable);
                    bytesAvailable = fileInputStream.available();
                    bytesAvailable = Math.min(bytesAvailable, maxBufferSize);
                    bytesRead = fileInputStream.read(buffer, 0, bytesAvailable);
                }

                // send multipart form data necesssary after file data...

                dos.writeBytes(lineEnd);
                dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);

                // close streams
                Log.e(Tag, "File is written");
                fileInputStream.close();
                dos.flush();
                dos.close();

            } catch (MalformedURLException ex) {
                Log.e(Tag, "error: " + ex.getMessage(), ex);
            }

            catch (IOException ioe) {
                Log.e(Tag, "error: " + ioe.getMessage(), ioe);
            }

            try {
                BufferedReader rd = new BufferedReader(new InputStreamReader(conn
                        .getInputStream()));
                String line;
                while ((line = rd.readLine()) != null) {
                    Log.e("Dialoge Box", "Message: " + line);
                }
                rd.close();

            } catch (IOException ioex) {
                Log.e("MediaPlayer", "error: " + ioex.getMessage(), ioex);
            }

请帮助我在哪里需要将我的ident字符串发送到php端! 非常感谢!

1 个答案:

答案 0 :(得分:1)

您可以通过MultipartEntity上传图片。

MultipartEntityHttpMime 4.0及更高版本的一部分。允许您将多个部分(由边界字符串分隔并使用给定的字符集编码)放入httppost请求。

有关详情以及如何使用Multipart,请参阅thisthis