Question

使用VB.Net和SQL Server

表1

Id             Value .....

1001P0010001   100
1001P0010002   200
1001P0010003   300
1001P0010004   400
...

我在table1的{{1}}中有n列和行，我希望使用新ID no ...复制所有列详细信息。

id no就像这个table1

1001P0020001, 1001P0020002, .......是下一个ID，P002是下一个ID .....

前4位数字和后4位数字将保留为P003的读数，中间4位数字应更改为下一个系列

预期输出

table1

哪种方法最好？

我可以在VB.Net或SQL查询中做到这一点......？请建议如何做到这一点。

Answer 1

CREATE TABLE CocoJambo (
    Id  CHAR(12) NOT NULL,
    Value INT NULL,
    CHECK( Id LIKE '[0-9][0-9][0-9][0-9][A-Z][0-9][0-9][0-9][0-9][0-9][0-9][0-9]' )
);
GO

CREATE UNIQUE INDEX IUN_CocoJambo_Id
ON CocoJambo (Id);
GO

INSERT  CocoJambo (Id, Value)
          SELECT '1001P0010001', 100
UNION ALL SELECT '1001P0010002', 200
UNION ALL SELECT '1001P0010003', 300
UNION ALL SELECT '1001P0010004', 400
UNION ALL SELECT '1001P0020001', 100
UNION ALL SELECT '1001P0020002', 200
UNION ALL SELECT '1001P0020003', 300
UNION ALL SELECT '1001P0020004', 400;
GO

-- Test 1: generating a single Id
DECLARE @Prefix CHAR(5),
        @Sufix CHAR(4);
SELECT  @Prefix = '1001P',
        @Sufix = '0001';

BEGIN TRAN

DECLARE @LastGeneratedMiddleValue  INT,
        @LastValue INT;

SELECT  @LastGeneratedMiddleValue = y.MiddleValue,
        @LastValue = y.Value
FROM 
    (
    SELECT  x.MiddleValue, x.Value,
            ROW_NUMBER() OVER(ORDER BY x.MiddleValue DESC) AS RowNum
    FROM 
        (
        SELECT  CONVERT(INT,SUBSTRING(a.Id,6,3)) AS MiddleValue, a.Value
        FROM    CocoJambo a WITH(UPDLOCK) -- It will lock the rows (U lock) during transaction
        WHERE   a.Id LIKE @Prefix+'%'+@Sufix
        ) x
    ) y
WHERE   y.RowNum=1;

SELECT  @LastGeneratedMiddleValue  = ISNULL(@LastGeneratedMiddleValue ,0)
SELECT  @Prefix
        +RIGHT('00'+CONVERT(VARCHAR(3),@LastGeneratedMiddleValue +1),3)
        +@Sufix AS MyNewId,
        @LastValue AS Value

COMMIT TRAN;
GO

-- Test 2: generating many Id's
BEGIN TRAN

DECLARE @Results TABLE (
    Prefix CHAR(5) NOT NULL,
    Sufix CHAR(4) NOT NULL,
    LastGeneratedMiddleValue  INT NOT NULL,
    LastValue INT NULL
);
INSERT  @Results (Prefix, Sufix, LastGeneratedMiddleValue, LastValue)
SELECT  y.Prefix, y.Sufix, y.MiddleValue, y.Value
FROM 
    (
    SELECT  x.Prefix, x.MiddleValue, x.Sufix, x.Value,
            ROW_NUMBER() OVER(PARTITION BY x.Prefix, x.Sufix ORDER BY x.MiddleValue DESC) AS RowNum
    FROM 
        (
        SELECT  SUBSTRING(a.Id,1,5) AS Prefix,
                CONVERT(INT,SUBSTRING(a.Id,6,3)) AS MiddleValue,
                SUBSTRING(a.Id,9,4) AS Sufix,
                a.Value
        FROM    CocoJambo a WITH(UPDLOCK) -- It will lock the rows (U lock) during transaction
        ) x
    ) y
WHERE   y.RowNum=1;

SELECT  r.*, 
        r.Prefix
        +RIGHT('00'+CONVERT(VARCHAR(3),r.LastGeneratedMiddleValue +1),3)
        +r.Sufix AS MyNewId,
        r.LastValue AS Value
FROM    @Results r;

COMMIT TRAN;
GO

Answer 2

insert into table1 (id, value)
select 
    l +
    replicate('0', 3 - lenght(m)) + m +
    r,
    value
from (
    select 
        left(id, 5) l,
        cast(cast(substring(id, 6, 3) as integer) + 1 as varchar(3)) m,
        right(id, 4),
        value
    from table1
) s

如何生成新代码

2 个答案: