每次我进行休息呼叫localhost:8080 / user / 1时,它会创建一个新的用户服务对象,而不是使用在服务器启动期间创建的用户服务对象。我在使用Jersey和Spring。
的applicationContext.xml
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.1.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.1.xsd"
default-autowire="byName"
>
<bean class="org.springframework.beans.factory.annotation.AutowiredAnnotationBeanPostProcessor"/>
<context:annotation-config/>
<context:component-scan base-package="com.gigenginecore.platform.dataaccess.impl" />
<context:component-scan base-package="com.gigengine.dataaccess"/>
<context:component-scan base-package="com.gigengine.dataaccess.impl"/>
<context:component-scan base-package="com.gigenginecore.platform.service" />
<context:component-scan base-package="com.gigengine.service" />
<context:component-scan base-package="com.gigenginecore.provider" />
</beans>
///// UserService类的代码片段,我甚至试图强制范围为单例。
@Service
@Scope("singleton")
@Path("/user")
public class UserService extends AbstractUserService {
///from my web.xml
<servlet>
<servlet-name>jersey-servlet</servlet-name>
<servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class>
<init-param>
<param-name>com.sun.jersey.config.property.packages</param-name>
<param-value>com.gigengine.service,com.gigenginecore.platform.service, com.gigenginecore.provider</param-value>
</init-param>
<init-param>
<param-name>com.sun.jersey.api.json.POJOMappingFeature</param-name>
<param-value>true</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>jersey-servlet</servlet-name>
<url-pattern>/*</url-pattern>
</servlet-mapping>
///// 所有DAO都会在启动时正确实例化并注入到用户服务类中,但是当我调用服务端点本身时,它会创建一个新的UserService类,其中DAO为null。
我需要做些什么来抓住在启动时创建的那个?不确定为什么它在创建一个“Spring”单例时会创建一个新实例。
有什么建议吗?
答案 0 :(得分:4)
使用Jersey with Spring时,请使用com.sun.jersey.spi.spring.container.servlet.SpringServlet
代替com.sun.jersey.spi.container.servlet.ServletContainer
。见http://jersey.java.net/nonav/apidocs/latest/jersey/contribs/jersey-spring/com/sun/jersey/spi/spring/container/servlet/package-summary.html