Question

我尝试修改长轮询代码以适应我的情况。我想从mysql中计算总数，如果数字发生变化（增加或减少），它会通知我。

问题是while循环保持循环。我怎么能阻止它？我只需要在总和变化时收到通知。

<?php
include("db.php");
$result = mysql_query("SELECT sum( r ) as totalsum FROM (SELECT colA, colB, COUNT( * ) AS r FROM product GROUP BY productid ) AS t");
while($row = mysql_fetch_array($result))
{
    $old_totalsum = $row['totalsum']; 
}

?>
<html>
<head>
<script src="http://code.jquery.com/jquery-latest.min.js" type="text/javascript"></script>
<script type="text/javascript" charset="utf-8">

var old_totalsum =<?php echo $old_totalsum; ?>;
function waitForMsg(){
$.ajax({
    type: "GET",
    url: "poll.php?old_totalsum=" + old_totalsum,
    async: true,
    cache: false,
        success: function(data){

        var json = "eval(+(" + data + ")+)";
    if(json['msg'] != "") {

        alert(data); 
    }

    old_msg_id = json['old_msg_id']; 
    setTimeout('waitForMsg()',1000);
    },
    error: function(XMLHttpRequest, textStatus, errorThrown){
    alert("error: " + textStatus + " (" + errorThrown + ")");
    setTimeout('waitForMsg()',15000);
    }


    });  // end ajax
} //end waitformsg


$(document).ready(function(){ 
 waitForMsg();
});

</script>
</head>
<body>
<div id="chat">
</div>
</body>
</html>
<----------------------------------------------------------->

poll.php
<----------------------------------------------------------->
<?php
include("db.php");

$old_totalsum = $_GET['old_totalsum']; 


$result = mysql_query("SELECT sum( r ) as totalsum FROM (SELECT colA, colB, COUNT( * ) AS r FROM product GROUP BY productid ) AS t");
while($row = mysql_fetch_array($result))
{
    $last_sum = $row['totalsum']; 
}



while($last_sum < $old_totalsum || $last_sum > $old_totalsum)


    while($last_sum <= $old_totalsum)
    {
    usleep(1000);
    clearstatcache();
    $result = mysql_query("SELECT sum( r ) as totalsum FROM (SELECT colA, colB, COUNT( * ) AS r FROM product GROUP BY productid ) AS t");
        while($row = mysql_fetch_array($result))
        {
         $last_sum = $row['totalsum'];
            //echo $last_sum;
            //return;
        }

    }





$response = array();
$response['msg'] = 'new';
$response['old_msg_id'] = $last_sum;
echo json_encode($response);
?>
<------------------------------------------->

Answer 1

我期待这样的逻辑：

$latest_sum= -1;
// Loop until sum from DB is different from what was passed  in
while( $latest_sum == -1 || $latest_sum!= $old_sum ){
  $result = mysql_query("SELECT sum( r ) as totalsum FROM (SELECT colA, colB, COUNT( * ) AS r FROM product GROUP BY productid ) AS t");
   while($row = mysql_fetch_array($result))
   {
      $lastest_sum = $row['totalsum']; 
   }
}

$response = array();
$response['msg'] = 'new';
$response['old_msg_id'] = $latest_sum;
echo json_encode($response);

如果需要很长时间才能更改，那么Apache（或运行PHP的任何内容）可能会取消该请求。这也将在db上运行大量查询，这是非常昂贵的。

所以最好将你的循环放在javascript中。它会调用一个只返回数据库中最新总和的函数。 javascript应该在每个请求之间等待一秒或更长时间。

如果数据库的性能仍然太难，那么php应该以某种方式每分钟缓存一次值并返回缓存的值。

长期民意调查不会停止

1 个答案: