Question

我无法在托管类中初始化静态本机指针。

以下是详细信息：我创建了一个C ++ / CLI控制台项目，并在其中声明了一个静态非托管指针。但是我无法用任何方法初始化静态指针（但是如果我将指针放入匿名命名空间，那么就没有问题，在代码中进行了演示）。你遇到过类似情况并找到解决办法吗？

代码在这里：

class MyTask
{
public:
    int m_index;
    MyTask()
    {
        m_index = 0;
    }
};

namespace
{
    static MyTask* s_pTask;
}

public ref class MyApplication
{
public:
    static MyTask* sm_pTask;

    static void InitizlizeStaticMembers(MyTask* pTask)
    {
        sm_pTask = pTask;
    }

    void AddTask()
    {
        sm_pTask = new MyTask();
    }
};

void main()
{
    MyApplication^ app = gcnew MyApplication();

    // 1st, doesn't work (sm_pTask is still null after the execution)
    MyApplication::sm_pTask = new MyTask();
    // 2nd, doesn't work (pTask can be initialized correctly, sm_pTask is still null after the execution)
    MyTask* pTask = new MyTask();
    MyApplication::InitizlizeStaticMembers(pTask);
    // 3rd, doesn't work (sm_pTask is still null after the execution)
    app->AddTask();
    // 4th, work(s_pTask can be initialized correctly)
    s_pTask = new MyTask();
}

Answer 1

我发现（使用VS2005）调试器确认你所说的内容 - 指针的值在更新时不会改变。但是如果你输出一些东西，代码实际上是有效的。

我相信这是调试器中的错误。

Answer 2

我没有看到代码有任何问题，它对我来说很好。不需要匿名命名空间。

#include "stdafx.h"
#include <iostream>

class MyTask
{
public:
    int m_index;
    MyTask()
    {
        m_index = 0;
    }
};

static MyTask* s_pTask;

public ref class MyApplication
{
public:
    static MyTask* sm_pTask = NULL;

    static void InitizlizeStaticMembers(MyTask* pTask)
    {
        sm_pTask = pTask;
    }

    void AddTask()
    {
        sm_pTask = new MyTask();
    }
};

void main()
{
    MyApplication^ app = gcnew MyApplication();

    // 1st, doesn't work (sm_pTask is still null after the execution)
    std::cout << "MyApplication::sm_pTask before new " << MyApplication::sm_pTask << '\n'; // 0
    MyApplication::sm_pTask = new MyTask();
    std::cout << "MyApplication::sm_pTask after new " << MyApplication::sm_pTask << '\n'; // 003B8170

    MyTask* pTask = new MyTask();
    std::cout << "pTask= " << pTask << '\n'; // 003B81A0
    MyApplication::InitizlizeStaticMembers(pTask);
    std::cout << "MyApplication::sm_pTask = " << MyApplication::sm_pTask << '\n'; // 003B81A0

    app->AddTask();    
    s_pTask = new MyTask();
}

如何在C ++ / CLI代码中初始化非托管静态指针？

2 个答案: