我很好奇为什么会这样。我今天早些时候遇到了这种情况
using (SqlConnection oConn = new SqlConnection(ConnectionString))
{
using (SqlCommand cmd = new SqlCommand("IC_Expense_InsertCycle", oConn))
{
cmd.CommandType = CommandType.StoredProcedure;
cmd.Parameters.AddWithValue("@PortalId", portalId);
cmd.Parameters.AddWithValue("@Description", description);
cmd.Parameters.AddWithValue("@StartDate", start);
cmd.Parameters.AddWithValue("@EndDate", end);
try
{
oConn.Open();
cmd.ExecuteNonQuery();
}
catch (SqlException ex)
{
throw ex;
}
}
}
//Get the new set of ExpenseCycles for binding
ExpenseCycle cycle = new ExpenseCycle(ConnectionString);
return cycle.GetExpenseCycles(portalId);
// ^^ this works just fine. The GetExpenseCycles call will basically set up the structure above with using SqlConnection and using SqlCommand
using (SqlConnection oConn = new SqlConnection(ConnectionString))
{
using (SqlCommand cmd = new SqlCommand("IC_Expense_InsertCycle", oConn))
{
cmd.CommandType = CommandType.StoredProcedure;
cmd.Parameters.AddWithValue("@PortalId", portalId);
cmd.Parameters.AddWithValue("@Description", description);
cmd.Parameters.AddWithValue("@StartDate", start);
cmd.Parameters.AddWithValue("@EndDate", end);
try
{
oConn.Open();
cmd.ExecuteNonQuery();
}
catch (SqlException ex)
{
throw ex;
}
//Get the new set of ExpenseCycles for binding
ExpenseCycle cycle = new ExpenseCycle(ConnectionString);
return cycle.GetExpenseCycles(portalId);
//This didn't work. The INSERT statement was successful, but it was bringing back old entries, and did not include the newest one that was just inserted
}
}
底层代码块最初是我的,我的测试环境的返回计数只有1,但数据库中有2条记录。它没有取出新插入的记录。
GetExpenseCycles的基本代码如下:
using (SqlConnection oConn = new SqlConnection(ConnectionString))
{
using (SqlCommand cmd = new SqlCommand("IC_Expense_GetExpenseCyclesByPortal",oConn))
{
oConn.Open();
using (SqlDataReader sdr = cmd.ExecuteReader())
{
//Read List<expensecycle> here
}
}
}
任何想法为什么?没有例外。
答案 0 :(得分:3)
没有抛出异常所以没有错误......我怀疑连接上的隔离级别
在第一种情况下,连接不会重叠。
ExpenseCycle()使用连接字符串,我可以安全地假设它开始一个新的连接。
在第二个示例(问题情况)中,连接重叠:
如果隔离级别是例如读取提交的并且“封闭”连接尚未稳定其写入(提交),则新连接不会获取更改,在这种情况下是插入。
可能的解决方案或尝试的事项: 1.检查连接上的隔离级别 2.将连接而不是连接字符串传递给ExpenseCycle()(这是一种更好的做法)
答案 1 :(得分:1)
您可能有一个环境事务生效(如果在事务范围内调用代码块,新连接将自动加入该事务。使用TransactionScope class,您可以获得该事务的句柄,在第二次通话之前提交。
此外,您的第二次调用似乎在命令的使用块范围内。将它移到那里可能足以解决你的问题
using (SqlConnection oConn = new SqlConnection(ConnectionString))
{
using (SqlCommand cmd = new SqlCommand("IC_Expense_InsertCycle", oConn))
{
cmd.CommandType = CommandType.StoredProcedure;
cmd.Parameters.AddWithValue("@PortalId", portalId);
cmd.Parameters.AddWithValue("@Description", description);
cmd.Parameters.AddWithValue("@StartDate", start);
cmd.Parameters.AddWithValue("@EndDate", end);
try
{
oConn.Open();
cmd.ExecuteNonQuery();
}
catch (SqlException ex)
{
throw ex;
}
}//close the SqlCommand
//Get the new set of ExpenseCycles for binding
ExpenseCycle cycle = new ExpenseCycle(ConnectionString);
return cycle.GetExpenseCycles(portalId);
//This might fix your problem.
}
另一种选择是将第二个调用移出第一个使用块之外,如此
bool insertSuccessful;
using (SqlConnection oConn = new SqlConnection(ConnectionString))
{
using (SqlCommand cmd = new SqlCommand("IC_Expense_InsertCycle", oConn))
{
cmd.CommandType = CommandType.StoredProcedure;
cmd.Parameters.AddWithValue("@PortalId", portalId);
cmd.Parameters.AddWithValue("@Description", description);
cmd.Parameters.AddWithValue("@StartDate", start);
cmd.Parameters.AddWithValue("@EndDate", end);
try
{
oConn.Open();
cmd.ExecuteNonQuery();
insertSuccessful=true;
}
catch (SqlException ex)
{
insertSuccessful=false
throw ex;
}
}//close the SqlCommand
}//close the connection
//Get the new set of ExpenseCycles for binding
if(insertSuccessful)
{
ExpenseCycle cycle = new ExpenseCycle(ConnectionString);
return cycle.GetExpenseCycles(portalId);
}
我认为第一个块应该可以解决您的问题。如果不是第二个肯定应该。