修改
我现在有了这段代码:
public void sendMessage(View view) {
Intent intent = new Intent(this, DisplayMessageActivity.class);
EditText editText = (EditText) findViewById(R.id.enter_name);
String message = editText.getText().toString();
intent.putExtra(EXTRA_MESSAGE, message);
EditText editText1 = (EditText) findViewById(R.id.enter_age);
String message1 = editText1.getText().toString();
intent.putExtra(EXTRA_MESSAGE, message1);
EditText editText2 = (EditText) findViewById(R.id.enter_height);
String message2 = editText2.getText().toString();
intent.putExtra(EXTRA_MESSAGE, message2);
EditText editText3 = (EditText) findViewById(R.id.enter_weight);
String message3 = editText3.getText().toString();
intent.putExtra(EXTRA_MESSAGE, message3);
EditText editText4 = (EditText) findViewById(R.id.enter_gender);
String message4 = editText4.getText().toString();
intent.putExtra(EXTRA_MESSAGE, message4);
startActivity(intent);
}
}
我如何同时从所有这些窗口中删除所有信息?因为我想将其保存在用户配置文件中。目前这是我的代码,但我只是从“enter_gender”获得信息。
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
// Get the message from the intent
Intent intent = getIntent();
String message = intent.getStringExtra(NutritionHandler.EXTRA_MESSAGE);
// Create the text view
TextView textView = new TextView(this);
textView.setTextSize(40);
textView.setText(message);
// Set the text view as the activity layout
setContentView(textView);
}
答案 0 :(得分:0)
我认为您可以通过重复代码的第3,4和5行来轻松实现它,只需更改ID。
答案 1 :(得分:0)
尝试以下,
你的Xml
<EditText
android:id="@+id/edtName"
android:layout_height="40dp"
android:layout_below="@+id/txtName"
android:background="@drawable/edittext"
android:layout_width="fill_parent"
android:layout_marginRight="5dip"
android:hint="@string/hnt_name"
android:layout_marginLeft="5dip"
android:inputType="textCapSentences"
/>
<EditText
android:id="@+id/edtAge"
android:layout_height="40dp"
android:layout_below="@+id/txtEmailid"
android:background="@drawable/edittext"
android:layout_width="fill_parent"
android:layout_marginRight="5dip"
android:layout_marginLeft="5dip"
android:hint="@string/hnt_emailid"
android:inputType="textEmailAddress"
/>
在你的Oncreate中
EditText name = (EditText) findViewById(R.id.edtName);
EditText age = (EditText) findViewById(R.id.edtAge);
获取此值
String var_name = name.getText().toString();
String var_age = age.getText().toString();
希望有所帮助