这个标题有很多问题,但我找不到答案。
我做错了什么?
CREATE TABLE J
(A integer)
;
INSERT INTO J (A)
VALUES
(1),
(2),
(3),
(4),
(5),
(6),
(7),
(8),
(9),
(10)
;
仅create
有效。问题只是插入。我试过SQL Fiddle。
答案 0 :(得分:6)
您可以采取多种方式(参见SQL Fiddle with Demo):
INSERT ALL
INTO J (A) VALUES (1)
INTO J (A) VALUES (2)
INTO J (A) VALUES (3)
INTO J (A) VALUES (4)
INTO J (A) VALUES (5)
INTO J (A) VALUES (6)
INTO J (A) VALUES (7)
INTO J (A) VALUES (8)
SELECT * FROM dual
;
或(见SQL Fiddle With Demo):
INSERT INTO J (A)
select (1) from dual union all
select (2) from dual union all
select (3) from dual union all
select (4) from dual union all
select (5) from dual union all
select (6) from dual union all
select (7) from dual union all
select (8) from dual union all
select (9) from dual union all
select (10) from dual
甚至为每个语句单独INSERT
语句:
INSERT INTO J (A) VALUES (1);
INSERT INTO J (A) VALUES (2);
INSERT INTO J (A) VALUES (3);
INSERT INTO J (A) VALUES (4);
INSERT INTO J (A) VALUES (5);
INSERT INTO J (A) VALUES (6);
答案 1 :(得分:1)
您正在向1列表中添加多个值。
你需要
Insert into J (A)
values (1);
Insert into J (A)
values (2);
等
答案 2 :(得分:1)
尝试:
INSERT INTO J (A) VALUES (1);
INSERT INTO J (A) VALUES (2);
INSERT INTO J (A) VALUES (3);
INSERT INTO J (A) VALUES (4);
...
INSERT INTO J (A) VALUES (10);