Question

如果我在层次结构的基类中创建一个静态const，我可以在派生类中重新定义它的值吗？

编辑：

#include <iostream>

class Base
{
public:
  static const int i = 1;
};

class Derived : public Base
{
public:
  static const int i = 2;
};

int main()
{
  std::cout << "Base::i == " << Base::i << std::endl;
  std::cout << "Derived::i == " << Derived::i << std::endl;  

  Base * ptr;

  ptr= new Derived;

  std::cout<< "ptr=" << ptr->i << std::endl;

  return 0;
}

... ptr是指Base::i，这是不受欢迎的。

Answer 1

通过ptr访问静态成员是通过其声明的类型Base *而不是其运行时类型（有时是Base *，有时是Derived *）。您可以通过以下简单的程序扩展来看到这一点：

#include <iostream>

class Base
{
public:
    static const int i = 1;
};

class Derived : public Base
{
public:
    static const int i = 2;
};

int main()
{
    std::cout << "Base::i == " << Base::i << std::endl;
    std::cout << "Derived::i == " << Derived::i << std::endl;  

    Base *b_ptr = new Derived;
    std::cout<< "b_ptr=" << b_ptr->i << std::endl;

    Derived *d_ptr = new Derived;
    std::cout<< "d_ptr=" << d_ptr->i << std::endl;

    return 0;
}

输出：

Base::i == 1
Derived::i == 2
b_ptr=1
d_ptr=2

Answer 2

没有。它是const，因此您无法修改其值。

但是你可以为派生类声明一个同名的新static const，并在那里定义它的值。

#include <iostream>

class Base
{
public:
  static const int i = 1;
};

class Derived : public Base
{
public:
  static const int i = 2;
};

int main()
{
  std::cout << "Base::i == " << Base::i << std::endl;
  std::cout << "Derived::i == " << Derived::i << std::endl;  
  return 0;
}

Answer 3

您必须在构造函数成员初始化列表中启动const成员变量。

你无法修改const变量。

在派生类C ++中重新定义静态const值

3 个答案: