Jackson JSON Views被忽略了

时间:2012-10-12 01:09:09

标签: json spring spring-mvc jackson

我正在尝试将Jackson2.0与Spring3.1一起使用,以便我可以使用jackson-Module-Hibernate。我已按照此处所述的步骤http://blog.pastelstudios.com/2012/03/12/spring-3-1-hibernate-4-jackson-module-hibernate/进行操作。所有这些似乎工作正常,但是当我尝试使用JSON视图以便JSON只包含视图中的字段时它不起作用。

活动视图始终为null。如何使视图处于活动状态?我已经尝试了一天没有运气......任何帮助都将非常感激。提前谢谢。

以下是相关代码。

这是Mapper

import com.fasterxml.jackson.databind.ObjectMapper;
import com.fasterxml.jackson.datatype.hibernate4.Hibernate4Module;

public class HibernateAwareObjectMapper extends ObjectMapper {

public HibernateAwareObjectMapper() {
    Hibernate4Module hm = new Hibernate4Module();
    registerModule(hm);  
    hm.configure(Hibernate4Module.Feature.FORCE_LAZY_LOADING, true);
}

}

这是视图类

public class DiffViews {
 public static class Public { }

}

这是我使用视图的POJO

 @JsonIdentityInfo(generator=ObjectIdGenerators.IntSequenceGenerator.class, property="@id")
 @JsonIgnoreProperties(ignoreUnknown=true)
 @Entity
 public class Premium implements java.io.Serializable {

@JsonView(DiffViews.Public.class)
private String sequence;
@JsonView(DiffViews.Public.class)

@Column(name = "SEQUENCE", nullable = false, length = 4)
public String getSequence() {
    return this.sequence;
}

public void setSequence(String sequence) {
    this.sequence = sequence;
}

@Column(name = "NAME", nullable = false)
public String getName() {
    return this.name;
}

public void setName(String name) {
    this.name = name;
}

在我的弹簧控制器中

@RequestMapping("/cartonPremium")
public void listAll(
        @RequestParam("page") int page, @RequestParam("rows") int maxResults, 
        @RequestParam("sidx") String sortKey, @RequestParam("sord") String sortOrder, HttpServletResponse response) {

    HibernateAwareObjectMapper mapper = new HibernateAwareObjectMapper();
    mapper.disable(SerializationFeature.FAIL_ON_EMPTY_BEANS);
    mapper.disable(SerializationFeature.WRITE_DATES_AS_TIMESTAMPS);
    mapper.enable(SerializationFeature.WRITE_CHAR_ARRAYS_AS_JSON_ARRAYS);
    mapper.disable(MapperFeature.DEFAULT_VIEW_INCLUSION );

    JqgridResponse<Premium> gridResponse = new JqgridResponse<Premium>();
    gridResponse.setRows(premiumList);
    gridResponse.setRecords(""+premiumList.size());
    gridResponse.setTotal(""+premiumList.size());
    gridResponse.setPage(""+page);      

    try {
        ObjectWriter objWriter= mapper.writerWithView(DiffViews.Public.class);
        Class<?> xxx = mapper.getSerializationConfig().getActiveView();
        objWriter.writeValue(response.getOutputStream(), gridResponse);
        //mapper.writerWithView(DiffViews.Public.class).writeValue(response.getOutputStream(), gridResponse);
    } catch (JsonGenerationException e) {
        e.printStackTrace();
    } catch (JsonMappingException e) {
        e.printStackTrace();
    } catch (IOException e) {
        e.printStackTrace();
    }
}

我的春季配置

    <mvc:annotation-driven>
    <mvc:message-converters>    
        <bean class="com.creata.json.MappingJackson2HttpMessageConverter">        
            <property name="objectMapper">            
                <bean class="com.creata.json.HibernateAwareObjectMapper" />        
            </property>    
        </bean>
    </mvc:message-converters>
</mvc:annotation-driven>

1 个答案:

答案 0 :(得分:0)

我终于找到了我的错误...我在一个名为JqgridResponse的包装器中返回我的域POJO,并且我没有在这个包装类的字段中添加@JsonView注释。所以一切都很好json视图不会被忽略。