我收到错误:
无法将参数值从SqlParameter转换为String。
我传入:
TestUsername,
TestPassword,
TestFirstName,
TestLastName,
TestEmail@Email.Com
代码:
try
{
Console.WriteLine("Inputs: Username, Password, First Name, Last Name, Email");
Console.WriteLine("Username: ");
string usernameInput = Console.ReadLine();
Console.WriteLine("Password: ");
string passwordInput = Console.ReadLine();
Console.WriteLine("First Name: ");
string firstNameInput = Console.ReadLine();
Console.WriteLine("Last Name: ");
string lastNameInput = Console.ReadLine();
Console.WriteLine("Email: ");
string emailInput = Console.ReadLine();
SqlCommand createLogin = new SqlCommand("INSERT INTO [dbo].[Users] VALUES ('@username', '@password', '@firstname', '@lastname', '@email')", myConnection.SqlConnection);
SqlParameter usernameParam = createLogin.Parameters.Add("@username", SqlDbType.VarChar, 40);
SqlParameter passwordParam = createLogin.Parameters.Add("@password", SqlDbType.VarChar, 50);
SqlParameter firstNameParam = createLogin.Parameters.Add("@firstname", SqlDbType.VarChar, 40);
SqlParameter lastNameParam = createLogin.Parameters.Add("@lastname", SqlDbType.VarChar, 40);
SqlParameter emailParam = createLogin.Parameters.Add("@email", SqlDbType.VarChar, 40);
usernameParam.Value = usernameInput;
passwordParam.Value = passwordInput;
firstNameParam.Value = firstNameInput;
lastNameParam.Value = lastNameInput;
emailParam.Value = emailParam;
createLogin.ExecuteNonQuery();
Console.WriteLine("Username: {0} with Password: {1} created.", usernameInput, EncDec.Decrypt(passwordInput, "testEncryption"));
}
catch (Exception CreateLoginException)
{
Console.WriteLine(CreateLoginException);
}
答案 0 :(得分:7)
您的参数声明和值设置都很好。您的代码唯一的问题是,您已将参数括在单引号中,这使得它成为字符串而不再是参数。在查询中删除参数周围的单引号
SqlCommand createLogin = new SqlCommand(
"INSERT INTO [dbo].[Users]
VALUES (@username, @password, @firstname, @lastname, @email",
myConnection.SqlConnection);
Command
对象会自动为您处理。
答案 1 :(得分:1)
应该是
createLogin.Parameters.AddwithValue("@parameter", parametervalue)
并删除其余的参数代码。
您无需使用AddWithValue
代替Add(