SELECT * FROM title
给出了以下输出:
title_number version_type hd_sd
1000046 Standard SD
1000046 Standard HD
1000050 Standard SD
1000093 Standard SD
1000093 Standard HD
1000125 Standard SD
1000269 Standard SD
我需要获取所有不同的title_numbers,然后hd_sd将= HD
如果存在,否则它将= SD
。正确的输出是:
title_number version_type hd_sd
1000046 Standard HD
1000050 Standard SD
1000093 Standard HD
1000125 Standard SD
1000269 Standard SD
我最接近的是SELECT * FROM title GROUP BY title_number
,但这并没有给我正确的hd_sd
列值。我如何正确地进行此查询?
答案 0 :(得分:2)
SELECT title_NUMBer, Version_type,
MIN(hd_sd)
FROM tableName
GROUP BY title_NUMBer
进行改进,
SELECT a.*
FROM tableName a
INNER JOIN
(
SELECT title_NUMBer, MIN(hd_sd) minCol
FROM tableName
GROUP BY title_NUMBer
) b ON a.title_number = b.title_Number AND
a.hd_sd = b.mincol