Question

我正在尝试填充dataTable，如下所示：

$("#my-datatable").dataTable( {
    "sAjaxSource" : "/someURLOnMyServer",
    "bDestroy" : true,
    "fnServerParams" : function(serverParams) {
        serverParams.push(
            {
                "name" : "widget",
                "value" : token
            }
        );
    }
});

它填充的HTML表格：

<table id="my-datatable">
    <thead>
        <tr>
            <th>Type</th>
            <th>Value</th>
            <th>ID</th>
            <th>Fizz</th>
            <th>Buzz</th>
        </tr>
    </thead>
    <tbody></tbody>
</table>

根据Firebug，从服务器返回的JSON是：

[
   {
      "id":1,
      "attributeType":{
         "id":1,
         "name":"test1",
         "tag":"test-type",
         "is-dog":false
      },
      "attributeValue":{
         "id":null,
         "name":"blah",
         "tag":"BLAH"
      },
      "buzz":1,
      "fizz":"53abc"
   }
]

但Firebug在其控制台中抛出以下JavaScript错误：

TypeError: aData is undefined
[Break On This Error]   

for ( i=0 ; i<aData.length ; i++ ) --> jquery.dataTables.js (line 2541)

有人能发现出了什么问题吗？要么我没有正确设置我的dataTable对象，要么返回的JSON与它试图填充的HTML表的“模式”不匹配。无论哪种方式，我都输了。提前谢谢！

Answer 1

数据表需要特定的结果格式。如果您不使用该格式，则必须声明所有内容。

$('#my-datatable').dataTable( {

    "sAjaxSource": "/url/here",


    "fnServerData": function ( sSource, aoData, fnCallback ) {
            aoData.push( { "name": "widget", "value": "token" } );

            request = $.ajax({
              "dataType": 'json', 
              "type": "GET", 
              "url": sSource, 
              "data": aoData, 
              "success": fnCallback
            });
      },


      "aoColumns": [
            { "mDataProp": "id"},
            { "mDataProp": "fizz"},
            { "mDataProp": "name"},
            { "mDataProp": "tag"},
            { "mDataProp": "tag"},
            { "mDataProp": "attributeValue.name"},
            { "mDataProp": "attributeValue.tag"},
        ],

    });

格式为：http://datatables.net/release-datatables/examples/server_side/post.html

Answer 2

尝试用aaData封装您的JSON对象，如：

{"aaData" : 

[{"id":1,"attributeType":{"id":1,"name":"test1","tag":"test-type","is-dog":false},"attributeValue":{"id":null,"name":"blah","tag":"BLAH"},"buzz":1,"fizz":"53abc"}]

}

为什么jQuery dataTables不能解析我的JSON？

2 个答案: