我遇到了这个问题,请帮忙: 我想读取一个txt文件并将内容放入ArrayList,格式如下:
name Yoshida Shuhei
birthday 8-04-1961
phone 0123456789
email abc@123.com
medicalHistory None
address 12 X Street, Suburb,
NSW, Australia
address 13 Y Street, Suburb, VIC, Australia
name Kazuo Hirai
medicalHistory None
email xyz@123.com
phone 0987654321
birthday 26-11-1972
该文件包含多个患者记录,并且每个患者记录块内的记录可以按任何顺序发生(例如,第一个患者的名称首先出现,但第二个患者的地址先来),所有记录都由空行分隔。
我的想法是,如果当前行不是空行,则开始阅读患者记录并将其添加到患者对象中,这是我的代码:
public static ArrayList<Patient> getData(String fileName) {
try {
File file = new File(fileName);
Scanner reader = new Scanner(file);
ArrayList<Patient> recordList = new ArrayList<Patient>();
ArrayList<MedicalHistory> mhList = new ArrayList<MedicalHistory>();
int index = -1;
int mh_index = -1;
String s;
Patient p = null;
MedicalHistory mh = null;
boolean addressActive = false;
boolean mhActive = false;
while (reader.hasNext()) {
s = reader.nextLine();
Scanner line = new Scanner(s);
String cmd;
if (!s.trim().isEmpty()) {
cmd = line.next();
if (cmd.equalsIgnoreCase("name")) {
index++;
p = new Patient();
p.setName(line.nextLine());
recordList.add(index, p);
addressActive = false;
mhActive = false;
} else if (cmd.equalsIgnoreCase("address")) {
if (line.hasNext()) {
p.setAddress(line.nextLine().trim());
recordList.set(index, p);
}
addressActive = true;
mhActive = false;
} else if (cmd.equalsIgnoreCase("birthday")) {
p.setBirthday(line.nextLine());
recordList.set(index, p);
addressActive = false;
mhActive = false;
} else if (cmd.equalsIgnoreCase("email")) {
if (line.hasNext()) {
p.setEmail(line.nextLine());
recordList.set(index, p);
}
addressActive = false;
mhActive = false;
} else if (cmd.equalsIgnoreCase("phone")) {
if (line.hasNextInt()) {
p.setPhone(line.nextInt());
recordList.set(index, p);
}
addressActive = false;
mhActive = false;
} else if (cmd.equalsIgnoreCase("medicalHistory")) {
mh = new MedicalHistory();
//...parse the medicalHistory
addressActive = false;
mhActive = true;
} else if (addressActive) {
String address = p.getAddress() + " " + s.trim();
p.setAddress(address);
recordList.set(index, p);
} else if (mhActive) {
//to deal with multiple medical histories
} else
System.out.println("Error: no command:" + s);
}
}
reader.close();
return recordList;
} catch (Exception e) {
System.out.println("Error:- " + e.getMessage());
return null;
}
}
问题是,我的代码只能在名称出现时处理;如果第一个非空行以其他命令开头(例如以地址开头),则不会为其初始化新患者(),程序将获得错误...
那么我应该把 p = new Patient()放在哪里,无论命令的顺序是什么,程序都要读取患者记录,然后将数据存储在Patient对象中?
任何人都可以改进我的代码并满足这个条件吗?非常感谢!
答案 0 :(得分:1)
我建议您将每个块读入HashMap<String,String>
,将每个属性映射到文件中的值。当块完成时(即,当您看到空白行或文件末尾时),您可以按照所需的任何特定属性顺序处理块,以便正确创建Patient
对象。
或者,使用您当前的逻辑,您只需要稍微改变一下即可完成所需的操作:
. . .
while (reader.hasNext()) {
s = reader.nextLine();
Scanner line = new Scanner(s);
String cmd;
if (!s.trim().isEmpty()) {
if (p == null) {
// starting a new block -- create a new patient record
p = new Patient();
recordList.add(p);
}
if (cmd.equalsIgnoreCase("name")) {
index++;
p.setName(line.nextLine());
addressActive = false;
mhActive = false;
} else if (cmd.equalsIgnoreCase("address")) {
if (line.hasNext()) {
p.setAddress(line.nextLine().trim());
}
addressActive = true;
mhActive = false;
} else if (cmd.equalsIgnoreCase("birthday")) {
p.setBirthday(line.nextLine());
addressActive = mhActive = false;
} else if (cmd.equalsIgnoreCase("email")) {
if (line.hasNext()) {
p.setEmail(line.nextLine());
}
addressActive = mhActive = false;
} else if (cmd.equalsIgnoreCase("phone")) {
if (line.hasNextInt()) {
p.setPhone(line.nextInt());
}
addressActive = mhActive = false;
} else if (cmd.equalsIgnoreCase("medicalHistory")) {
mh = new MedicalHistory();
//...parse the medicalHistory
addressActive = false;
mhActive = true;
} else if (addressActive) {
String address = p.getAddress() + " " + s.trim();
p.setAddress(address);
} else if (mhActive) {
//to deal with multiple medical histories
} else
System.out.println("Error: no command:" + s);
}
} else {
// blank line indicates end of block
p = null;
}
}
. . .
请注意,当您修改当前患者记录(由p
引用)时,您无需再次设置recordList
元素;它会自动更新,因为它引用了数组列表中已有的对象。有了这个,你根本不需要index
;您只需将新的患者记录添加到recordList
的末尾,并且只要输入仍在同一个区块中,就会继续修改它。
答案 1 :(得分:1)
我的想法是维护哈希表来存储完整的数据..
Hashtable<Integer,Hashtable<String,String>> ht = new Hashtable<Integer,Hashtable<String,String>>();
整数存储患者#,Hashtable存储名称,值对。
("address","<addr>"), ("name","<name>")
HashMap不是线程安全的..在多线程环境中运行时可能会出现问题。