Question

如何组合这两个数组？

$array1 = array("gif" => "gif", "jpg" => "jpeg", "jpeg" => "jpeg", "png" =>"png");
$array2 = array("gif" => "0", "jpg" => "90", "jpeg" => "90", "png" => "8");

我试过

$array1 = array("gif" => "gif" => "0", "jpg" => "jpeg" => "90", "jpeg" => "jpeg" => "90", "png" =>"png" => "8");

但当然没有任何帮助吗？

Answer 1

这似乎更有意义：

$arr = array("gif" => array("extension" => "gif", "size" => "90"),
             "jpg" => array("extension" => "jpeg", "size" => "120")

               ...
              );

echo "Extension: " . $arr['gif']['extension'] . " Size or whatever: " . $arr['gif']['size'];

循环遍历：

foreach($arr as $key => $val) {
    echo "Image Type: $key, Extension: " . $val['extension'] . ", Size: " . $val['size'];
}

Answer 2

每个键都有两个值。为具有多个值的每个键创建一个子数组：

$ar1 = array( 'key' => array('key1','key2') );

Answer 3

要建立我以前的答案，你最好使用并行数组：

$validTypes = array("gif" => "gif", "jpg" => "jpeg", "jpeg" => "jpeg", "png" => "png");
$quality = array("gif" => 0, "jpg" => 90, "jpeg" => 90, "png" => "png");
if (!array_key_exists($image_type, $validTypes)) {
    trigger_error("Not a valid image type", E_USER_WARNING);
    return NULL;
}

// ...

$inFunc = "imagecreatefrom" . $validTypes[$image_type];
$outFunc = "image" . $validTypes[$image_type];

// ...

$outFunc($image, $source_file, $quality[$image_type]);

不过，卡里姆的回答也很好。只是一个偏好问题。

Answer 4

$array1 = array("gif" => "gif", "jpg" => "jpeg", "jpeg" => "jpeg", "png" =>"png");
$array2 = array("gif" => "0", "jpg" => "90", "jpeg" => "90", "png" => "8");
$finalarray = (array_merge_recursive($array1,$array2));

$ finalarray的结构是：

Array
(
[gif] => Array
    (
        [0] => gif
        [1] => 0
    )

[jpg] => Array
    (
        [0] => jpeg
        [1] => 90
    )

[jpeg] => Array
    (
        [0] => jpeg
        [1] => 90
    )

[png] => Array
    (
        [0] => png
        [1] => 8
    )
)

Answer 5

不确定如何“组合”它们。我将假设您希望第一个数组中的每个键映射到第二个

中的值

 foreach($array1 as $k=>$v)
 {
   $a3[$k] = $array2[$v]
 }

给你

  $a3 = array('gif'=>'0', 'jpg'=>'90', 'jpeg'=>'90', 'png'=>'8');

但这与array2相同。也许

 foreach($array1 as $k=>$v)
 {
   $a3[$k] = array($array1[$k],$array2[$k]);
 }

给出

 $a3 = array('gif'=>array('gif',0),'jpg'=>array('jpeg',90)...)

Answer 6

我很惊讶，没有一个答案提到你的下面，这些答案基本上可以描述为"everything you ever wanted to know about PHP arrays but were afraid to ask"

结合2个php数组？

6 个答案: