Question

在我的web.xml中，我有以下映射

<servlet-mapping>
    <servlet-name>mySite</servlet-name>
    <url-pattern>*.html</url-pattern> 
</servlet-mapping>

<servlet-mapping>
    <servlet-name>mySite</servlet-name>
    <url-pattern>/articles/*</url-pattern> 
</servlet-mapping>

目前它处理文件扩展名为.html的网址。但是，我希望能够处理 http：// localhost：8080 / MySite-Web / articles / testMe 类型的网址，即任何没有文章扩展名的文件扩展名的路径。

我尝试过的弹簧贴图是。

@RequestMapping(value = "/articles/*")
public ModelAndView getArticles(HttpServletResponse response, HttpServletRequest request
        ) throws java.lang.Exception {

    System.out.println("Handle any path prefixed with /articles/ ");
    return null;
}

在我的Spring配置中我使用以下

<bean id="viewResolver" class="org.springframework.web.servlet.view.UrlBasedViewResolver">
    <property name="viewClass" value="org.springframework.web.servlet.view.JstlView" />
</bean>

编辑：

这是Dispatcher Servlet映射

<servlet>
        <description>
        servlet</description>
        <servlet-name>MySite</servlet-name>
        <servlet-class>
        org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <init-param>
            <param-name>contextConfigLocation</param-name>
            <param-value>classpath:MySite-web-context.xml</param-value>
        </init-param>
        <load-on-startup>1</load-on-startup>
    </servlet>

这是MySite-web.context.xml

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans" 
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns:tx="http://www.springframework.org/schema/tx" 
    xmlns:aop="http://www.springframework.org/schema/aop"
    xmlns:jee="http://www.springframework.org/schema/jee" 
    xmlns:context="http://www.springframework.org/schema/context"
    xmlns:lang="http://www.springframework.org/schema/lang"
    xmlns:security="http://www.springframework.org/schema/security"
    xsi:schemaLocation="http://www.springframework.org/schema/beans
      http://www.springframework.org/schema/beans/spring-beans-2.5.xsd
      http://www.springframework.org/schema/aop
      http://www.springframework.org/schema/aop/spring-aop-2.5.xsd
      http://www.springframework.org/schema/tx
      http://www.springframework.org/schema/tx/spring-tx-2.5.xsd
      http://www.springframework.org/schema/context 
      http://www.springframework.org/schema/context/spring-context-2.5.xsd
      http://www.springframework.org/schema/jee
      http://www.springframework.org/schema/jee/spring-jee-2.5.xsd
      http://www.springframework.org/schema/lang
      http://www.springframework.org/schema/lang/spring-lang-2.5.xsd
      http://www.springframework.org/schema/security 
      http://www.springframework.org/schema/security/spring-security-2.0.1.xsd">


    <tx:annotation-driven transaction-manager="transactionManager" />

    <bean id="beanNameViewResolver" class="org.springframework.web.servlet.view.BeanNameViewResolver" />

    <bean id="viewResolver" class="org.springframework.web.servlet.view.UrlBasedViewResolver">
        <property name="viewClass" value="org.springframework.web.servlet.view.JstlView" />
    </bean>

                <context:component-scan base-package="com.mysite" scoped-proxy="interfaces" />



<bean id="multipartResolver" class="org.springframework.web.multipart.commons.CommonsMultipartResolver">
<property name="maxUploadSize">
             <value>-1</value> <!-- 10MB limit  -->
         </property>
</bean>


</beans>

如果我映射到/ test

，看起来所有的路径信息都会在它到达RequestMapping时被剥离

@RequestMapping(value = "/test")

它可行，如果

I System.out.println（request.getPathInfo（））;我只是 / test 而没有 / articles ???

提前干杯。

Answer 1

将此添加到您的MySite-web.context.xml：

<mvc:annotation-driven/>
<bean id="handlerMapping" class="org.springframework.web.servlet.mvc.method.annotation.RequestMappingHandlerMapping">
    <property name="alwaysUseFullPath" value="true"/>
</bean>

不要忘记在顶部添加正确的mvc命名空间行：

xmlns:mvc="http://www.springframework.org/schema/mvc"

xsi:schemaLocation中的网址。

现在应该考虑解决映射的完整路径。

查看Spring Documentation了解详情。

使用spring进行Servlet映射

1 个答案: