我有两台服务器,一台是应用服务器,另一台是API服务器,API服务器从$_FILES
读取数据。
所以我的问题是如何将文件数据发送到API服务器,以便它可以在$_FILES
中获取数据?
我需要CURL才能做到这一点,没有任何形式的帖子。
谢谢,
WA
答案 0 :(得分:1)
这是一个通过POST发送带有php / cURL文件的简单脚本:
<?php
$target_url = 'http://127.0.0.1/accept.php';
//This needs to be the full path to the file you want to send.
$file_name_with_full_path = realpath('./sample.jpeg');
/* the at sign '@' is required before the
* file name.
*/
$post = array('extra_info' => '123456','file_contents'=>'@'.$file_name_with_full_path);
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL,$target_url);
curl_setopt($ch, CURLOPT_POST,1);
curl_setopt($ch, CURLOPT_POSTFIELDS, $post);
$result=curl_exec ($ch);
curl_close ($ch);
echo $result;
这是接受该文件的相应脚本。
<?php
$uploaddir = realpath('./') . '/';
$uploadfile = $uploaddir . basename($_FILES['file_contents']['name']);
if (move_uploaded_file($_FILES['file_contents']['tmp_name'], $uploadfile)) {
echo "File is valid, and was successfully uploaded.\n";
} else {
echo "Possible file upload attack!\n";
}
?>
答案 1 :(得分:0)
来自php.net
<?php
/* http://localhost/upload.php:
print_r($_POST);
print_r($_FILES);
*/
$ch = curl_init();
$data = array('name' => 'Foo', 'file' => '@/home/user/test.png');
curl_setopt($ch, CURLOPT_URL, 'http://localhost/upload.php');
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_POSTFIELDS, $data);
curl_exec($ch);
?>