我正在使用自定义列表开发应用程序。我压倒了列表中的触摸事件。 如果我滚动一次(触摸并向上或向下移动手指一次),列表滚动得很好。当我向上滚动列表而不离开列表(即触摸向上然后向下然后离开),在这种情况下列表没有正确滚动。因为action_move只调用了第一个滚动,即当我向下移动列表时,动作_移动没有被检测到。 如果有人试图这样做,请告诉我。 任何代码段都会有很大的帮助。
由于
答案 0 :(得分:2)
public boolean onTouchEvent(MotionEvent ev) {
final int action = ev.getAction();
if ((action == MotionEvent.ACTION_MOVE) && (mTouchState != TOUCH_STATE_REST)) {
Log.d("DB", " scrolling twice ");
scrolltwice = true;
return true;
}
final float x = ev.getX();
final float y = ev.getY();
switch(action & MotionEvent.ACTION_MASK){
case MotionEvent.ACTION_MOVE:
final int xDiff = (int) Math.abs(x - mLastMotionX);
yDiff = (int) (y - mLastMotionY);
final int ydif = (int) Math.abs(y - mLastMotionY);
final int touchSlop = mTouchSlop;
boolean xMoved = xDiff > touchSlop;
boolean yMoved = ydif > touchSlop;
if (xMoved || yMoved) {
if (yMoved) {
mTouchState = TOUCH_STATE_SCROLLING;
}
}
break;
case MotionEvent.ACTION_DOWN:
if (!mScroller.isFinished()) {
mScroller.abortAnimation();
}
// Remember location of down touch
mLastMotionX = x;
mLastMotionY = y;
break;
case MotionEvent.ACTION_CANCEL:
case MotionEvent.ACTION_UP:
final int myDiff = (int) (y - mLastMotionY);
if(mTouchState == TOUCH_STATE_SCROLLING){
scrolltwice = false;
if(!scrolltwice){
Log.d("DB", " ACTION_UP fetch new records ");
FetchRecords rec = new FetchRecords();
rec.execute();
if(yDiff < 0){ // fetching next slot of records
nextRecordId = nextRecordId + previousTotal;
if(nextRecordId > totalRowCount){
nextRecordId = nextRecordId - previousTotal;
}
}else if(yDiff > 0){ // fetching previous slot of records
nextRecordId = nextRecordId - previousTotal;
if(nextRecordId < 1){
nextRecordId = 0;
}
}
}
}
scrolltwice = false;
mTouchState = TOUCH_STATE_REST;
break;
}
return false;
}
//implement ontouch listener if the view is list pass it onTouchEvent
public boolean onTouch(View v, MotionEvent event) {
if(v.equals(objListView))
onTouchEvent(event);
return false;
}