Question

这是我在网络服务中的Json响应，我无法解析它。我想要做的是加载tableview中的数据，例如。 3.7作为节标题和行中的其他值。我该怎么做？？我想使用内置API没有第三方框架。

非常感谢任何帮助。

{"Links":{"3.7":[{"fld_app_download_id":"7111","fld_app_version_id":"1928","fld_date_added":"2012-10-04 08:40:38","fld_cracker":"vend3tta101","fld_download_link":"fiberupload.com","fld_url":"http:\/\/fiberupload.com\/pwzmodjshwhr\/1Password_Pro_(v3.7_v370009_Univ_os31)-vend3tta101.ipa","fld_status":"1"},{"fld_app_download_id":"7112","fld_app_version_id":"1928","fld_date_added":"2012-10-04 08:40:38","fld_cracker":"vend3tta101","fld_download_link":"depositfiles.com","fld_url":"http:\/\/depositfiles.com\/files\/eyhcw06b6","fld_status":"1"},{"fld_app_download_id":"7113","fld_app_version_id":"1928","fld_date_added":"2012-10-04 08:40:38","fld_cracker":"vend3tta101","fld_download_link":"turbobit.net","fld_url":"http:\/\/turbobit.net\/vyc5jkr5s51k.html","fld_status":"1"}]}}

Answer 1

你看过NSJSONSerialization班了吗？它处理JSON和属性列表之间的转换。

Answer 2

以简单的方式，看看下面的代码：

#import "YourViewController.h"

@interface NSDictionary(JSONCategories)
+(NSDictionary*)dictionaryWithContentsOfJSONURLString:(NSString*)urlAddress;
-(NSData*)toJSON;
@end
@implementation NSDictionary(JSONCategories)
+(NSDictionary*)dictionaryWithContentsOfJSONURLString:(NSString*)urlAddress{
NSData* data = [NSData dataWithContentsOfURL: [NSURL URLWithString: urlAddress] ];
__autoreleasing NSError* error = nil;
id result = [NSJSONSerialization JSONObjectWithData:data options:kNilOptions error:&error];
if (error != nil) return nil;
return result;
}
-(NSData*)toJSON{
NSError* error = nil;
id result = [NSJSONSerialization dataWithJSONObject:self options:kNilOptions error:&error];
if (error != nil) return nil;
return result;    
}
@end

@implementation YourViewController

-(IBAction)downloadData:(id)sender{

    NSString *yourResponseLink = @"YOUR RESPONSE LINK";
    NSURL *urlString = [NSURL URLWithString:urlWroteString];
    NSData* data = [NSData dataWithContentsOfURL:urlString];
    [self performSelectorOnMainThread:@selector(fetchedData:) withObject:data waitUntilDone:NO];

}

-(void)fetchedData:(NSData *)responseData {

    NSError* error;

    if (responseData == nil) {

        NSLog(@"NO DATA HAS BEEN FETCHED,ERROR = %@",error);

    }else{

        NSDictionary* json = [NSJSONSerialization JSONObjectWithData:responseData options:kNilOptions error:&error];
        NSArray *yourResponseArray = [json objectForKey:@"YOUR RESPONSE KEY"];

        NSLog("YOU RESPONSE IS = %@",yourResponseArray);

    }

}


@end

要显示响应中的数据，请注意您的数据存储在NSArray上，因此在 cellForRowAtIndexPath 中，请使用以下方法：

-(UITableViewCell *)tableView:(UITableView *)myTableView cellForRowAtIndexPath:(NSIndexPath *)indexPath{

    //initialize your cells normally and to display the data from your response use
    NSDictionary *yourSpecificData = [yourResponseArray objectAtIndex:[indexPath row]];

    //and finally display some text in the cell
    cell.textLabel.text = [yourSpecificData objectForKey:@"SOME KEY FROM RESPONSE"];

}

Answer 3

你可以在ios5中使用“NSJsonSerialization”; 查看代码

-(void) parseJsonData:(NSData *)data
{
    NSError *error;
    NSDictionary *json = [NSJSONSerialization JSONObjectWithData:data options:kNilOptions error:&error];
    if (json == nil) {
        NSLog(@"json parse failed \r\n");
        return;
    }
    NSArray *songArray = [json objectForKey:@"song"];
    NSLog(@"song collection: %@\r\n",songArray);

    _song = songArray;
    self.songIndex = 0;
    NSDictionary *song = [songArray objectAtIndex:0];
    NSLog(@"song info: %@\t\n",song);

}

解析UITableView iOS的Json

3 个答案: