Question

可能重复：
how to post to a form with jquery/ajax

如何通过Jquery Ajax将数据发布到服务器？

JQuery的

function postNewBaseLine() {
    var id = "300";
    $.ajax({
            type: "POST",
            url: "ManagerBaseKit.aspx/SetNewBaseVersion",
            contentType: "application/json; charset=utf-8",
            dataType: "json",
            data: id,
            success: function(data) {
                alert('success!');
            }
        });
}

CS

[WebMethod]
public static void SetNewBaseVersion(string version)
{
    // I want it here!
}

我正在使用脚本管理器

<asp:ScriptManager ID="ScriptManager1" EnablePageMethods="true" EnablePartialRendering="true"
    runat="server" />

修改在更改为data: { 'version': id },

之后

我到了 POST _http：// localhost：49852 / ManagerBaseKit.aspx / SetNewBaseVersion 500（内部服务器错误）

Answer 1

您需要将数据对象更改为：

function postNewBaseLine() {
    var id = "300";
    $.ajax({
            type: "POST",
            url: "ManagerBaseKit.aspx/SetNewBaseVersion",
            contentType: "application/json; charset=utf-8",
            dataType: "json",
            data: {version: id},
            success: function(data) {
                alert('success!');
            }
        });
}

Answer 2

首先将ID更改为对象，我相信引号很重要。

function postNewBaseLine() {
var id = "300";
$.ajax({
        type: "POST",
        url: "ManagerBaseKit.aspx/SetNewBaseVersion",
        contentType: "application/json; charset=utf-8",
        dataType: "json",
        data: {"version": id},
        success: function(data) {
            alert('success!');
        }
    });

}

您可能还需要为服务方法添加一些属性

          [WebMethod]
          [WebInvoke(Method = "POST", RequestFormat = WebMessageFormat.Json, ResponseFormat = WebMessageFormat.Json, bodystyle = WebMessageBodyStyle.WrappedRequest)]
            public static void SetNewBaseVersion(string version)
            {
                // I want it here!
            }

JQuery $ .ajax如何将数据发布到服务器

2 个答案: