Android SQLite漏掉了

时间:2012-10-09 13:49:39

标签: android sqlite

我遇到了sql handler

的问题
A SQLiteConnection object for database '/data/data/.../databases/queueManager' was leaked!  Please fix your application to end transactions in progress properly and to close the database when it is no longer needed.

取自Androidhive教程并根据我的使用进行定制

表格看起来像

+ ----------------------------------------------------------- +
: DATABASE_ID : DATABASE_QID : DATABASE_QUEUE : DATABASE_DATE :
+ ----------------------------------------------------------- +

代码

   DBQueue searchDBqid(int id) {
       SQLiteDatabase db = this.getReadableDatabase();

        String selectQuery = "SELECT  * FROM " + TABLE_QUEUE + " WHERE " + DATABASE_QID + " = " + id; 

           Cursor cursornum = db.rawQuery(selectQuery, null);
           int dk = cursornum.getCount();
           cursornum.close();

           if (dk >0) {
               Cursor cursor = db.query(TABLE_QUEUE, new String[] { DATABASE_ID,
                       DATABASE_QID, DATABASE_QUEUE, DATABASE_DATE }, DATABASE_QID + "=?",
                       new String[] { String.valueOf(id) }, null, null, null, null);

               if (cursor != null) cursor.moveToFirst();

               DBQueue dbqueue = new DBQueue(Integer.parseInt(cursor.getString(0)),
                       cursor.getString(1), cursor.getString(2), cursor.getString(3));
               return dbqueue;
           }

       db.close();
       return null;
   }

   DBQueue getDBQueue(int id) {
       SQLiteDatabase db = this.getReadableDatabase();

       Cursor cursor = db.query(TABLE_QUEUE, new String[] { DATABASE_ID,
               DATABASE_QID, DATABASE_QUEUE }, DATABASE_ID + "=?",
               new String[] { String.valueOf(id) }, null, null, null, null);
       if (cursor != null)
           cursor.moveToFirst();

       DBQueue dbqueue = new DBQueue(Integer.parseInt(cursor.getString(0)),
               cursor.getString(1), cursor.getString(2), cursor.getString(3));
       return dbqueue;
   }


   public String getAllqid() {
       Time today = new Time(Time.getCurrentTimezone());
       today.setToNow();

       String selectQuery = "SELECT  * FROM " + TABLE_QUEUE + " WHERE " + DATABASE_DATE + " = '" + today.format("%d %m %Y") + "'";

       SQLiteDatabase db = this.getWritableDatabase();
       Cursor cursor = db.rawQuery(selectQuery, null);

       StringBuilder sb = new StringBuilder();       
       if (cursor.moveToFirst()) {
           do {
               if (sb.length() > 0) sb.append(',');
               sb.append(cursor.getString(1));
           } while (cursor.moveToNext());
       }

       String result = sb.toString();
       return result;
   }
   public void deleteDatedDBQueue() {
        Time today = new Time(Time.getCurrentTimezone());
        today.setToNow();
        String selectQuery = "SELECT  * FROM " + TABLE_QUEUE + " WHERE " + DATABASE_DATE + " != '" + today.format("%d %m %Y") + "'"; ;

        SQLiteDatabase db = this.getWritableDatabase();
        Cursor cursor = db.rawQuery(selectQuery, null);

        if (cursor.moveToFirst()) {
            do {
                db.delete(TABLE_QUEUE, DATABASE_ID + " = ?",
                       new String[] { String.valueOf(Integer.parseInt(cursor.getString(0))) });
            } while (cursor.moveToNext());
        }
        db.close();
    }
   public int getDBQueueCount() {
       String countQuery = "SELECT  * FROM " + TABLE_QUEUE;
       SQLiteDatabase db = this.getReadableDatabase();
       Cursor cursor = db.rawQuery(countQuery, null);
       cursor.close();

       return cursor.getCount();
   }
}

有人可以告诉我如何解决这个漏洞吗?

完整代码:http://ijailbreak.me/databasehandler.txt

4 个答案:

答案 0 :(得分:50)

完成后,应关闭每个Cursor。传统的做法是:

Cursor cursor = db.query(...);
try {
    // read data from the cursor in here
} finally {
    cursor.close();
}

但是现在,使用try-with-resources,它可以更加简洁:

try (Cursor cursor = db.query(...)) {
    // read data from the cursor in here
}

答案 1 :(得分:8)

您忘记多次关闭游标,确保在完成后始终关闭游标。

例如,第二个查询没有关闭光标,为了清楚起见,我已将其删除

如果您更改设计以使SQLiteDatabase成为getDBQueue,那么在getAllqidgetDBQueueCountSQLiteOpenHelper完成后,您也不会关闭SQLiteDatabase单身然后你不需要关闭 DBQueue searchDBqid(int id) { SQLiteDatabase db = this.getReadableDatabase(); String selectQuery = "SELECT * FROM " + TABLE_QUEUE + " WHERE " + DATABASE_QID + " = " + id; Cursor cursornum = db.rawQuery(selectQuery, null); int dk = cursornum.getCount(); cursornum.close(); if (dk >0) { // TODO: Close this cursor! Cursor cursor = db.query(TABLE_QUEUE, new String[] { DATABASE_ID, DATABASE_QID, DATABASE_QUEUE, DATABASE_DATE }, DATABASE_QID + "=?", new String[] { String.valueOf(id) }, null, null, null, null); if (cursor != null) cursor.moveToFirst(); DBQueue dbqueue = new DBQueue(Integer.parseInt(cursor.getString(0)), cursor.getString(1), cursor.getString(2), cursor.getString(3)); return dbqueue; } db.close(); return null; } 并避免泄漏

{{1}}

答案 2 :(得分:1)

每次打开数据库(可读或可写)时,必须使用“.close();”释放使用内存资源的游标。在每个数据库函数的使用结束后 例如:

 if (cursor != null) cursor.moveToFirst();

               DBQueue dbqueue = new DBQueue(Integer.parseInt(cursor.getString(0)),
                       cursor.getString(1), cursor.getString(2), cursor.getString(3));
               return dbqueue;
           }
cursor.close();

       db.close();
       return null;
   }

DBQueue getDBQueue(int id) {
       SQLiteDatabase db = this.getReadableDatabase();

       Cursor cursor = db.query(TABLE_QUEUE, new String[] { DATABASE_ID,
               DATABASE_QID, DATABASE_QUEUE }, DATABASE_ID + "=?",
               new String[] { String.valueOf(id) }, null, null, null, null);
       if (cursor != null)
           cursor.moveToFirst();

       DBQueue dbqueue = new DBQueue(Integer.parseInt(cursor.getString(0)),
               cursor.getString(1), cursor.getString(2), cursor.getString(3));
cursor.close();
db.close();
       return dbqueue;
   }

依旧...... !!

答案 3 :(得分:0)

第一次打开数据库并最后输入此代码。

 @Override
        protected void onDestroy() {
            // TODO Auto-generated method stub
         mdb.close();   
         super.onDestroy();
        }