Question

我有以下数据库表（虽然数据库中有更多数据，但这不是全部！）：

catid   value   description
0        350     350 euro
0        500     500 euro
0        650     650 euro
1        0       No
1        1       Yes

在PHP和json_encode（）的帮助下，我正在创建该表的JSON字符串：

jQuery171024539993586950004_1349776890005([{"0":"0","catid":"0","1":"350","value":"350","2":"350 euro","description":"350 euro"},{"0":"0","catid":"0","1":"500","value":"500","2":"500 euro","description":"500 euro"},{"0":"0","catid":"0","1":"650","value":"650","2":"650 euro","description":"650 euro"},{"0":"1","catid":"1","1":"0","value":"0","2":"No","description":"No"},{"0":"1","catid":"1","1":"1","value":"1","2":"Yes","description":"Yes"}])

现在我想要的是使用JSON来填充选择框，就像在HTML中一样：

<select id="0">
    <option value="350">350 euro</option>
    <option value="500">500 euro</option>
    <option value="650">650 euro</option>
</select>

<select id="1">
    <option value="0">No</option>
    <option value="1">Yes</option>
</select>

任何人都可以帮我吗？我知道怎么做一个循环来填充一个表（使用$ .getJSON），但我有点坚持这个。

Answer 1

此功能将遍历您发布的对象并填充菜单（给定您发布的来源）：

var populateSelects = function(data) {
    var cat0 = $('select#0'),
        cat1 = $('select#1'),
        opt = $('<option />'),
        newOpt = {},
        cat0opts = [],
        cat1opts = [];
    $.each(data, function(i, obj) {
        //clone the option element so as to not re-create a new one
        newOpt = opt.clone();
        //obj is the JavaScript object in the array, so
        //dot-notation works nicely
        newOpt.text(obj.description).val(obj.value);
        if (obj.catid === "0") {
            //push the DOM element, not the jQuery object
            cat0opts.push(newOpt[0]);
        } else if (obj.catid === "1") {
            cat1opts.push(newOpt[0]);
        }
    });
    //Add the array of DOM elements to their respective menus,
    //clearing out any existing menu items.
    cat0.empty().append(cat0opts);
    cat1.empty().append(cat1opts);
};

这里有一个小提琴：http://jsfiddle.net/a5MTE/1/

一个重要的注意事项是catid比较...如果解析的JSON将catid作为数字（不是字符串）返回，则您需要将比较更改为if (obj.catid === 0)。

Answer 2

通过json解析你应该做一个解析器，通过addcat上的if和else条件，你将能够做到这一点

使用JSON数据填充多个选择框

2 个答案: