Question

我在文本文件中有一个列表，它在名称和年龄之间交替显示。有9个名字和9个年龄。

我需要我的程序才能显示

人（此处插入名称）的年龄最高:(此处插入年龄）。

到目前为止，这是我的代码：

     public class Names 
     {


public static void main(String[] args) throws Exception
{

      // get textfile
      Scanner input = new Scanner( new File("names_and_ages.txt") );


final String[] names= new String[9];
final int[] ages= new int[9];
int counter = 0;

while (input.hasNext()) //while not end-of-file
{
    names[counter]=input.next();  
    ages[counter]=Integer.parseInt(input.next());
    counter++;

}
highestAge(names, ages);
input.close();
}//end of main

public static void highestAge (String[] name, int[] age)
{
    String name;
int count = 0;
int oldest = highestAge[count];
for ( int number: highestAge)
{
    if (number > oldest)
        {
        oldest = number;
        }
}
System.out.print("Person " + name + " has the highest age: " + oldest );
}//end of Size method

}//end of class

一切都编译我只是看不到让名字与年龄相匹配。帮助

Answer 1

如果你创建了一个Person类，你可以省去管理两个数组的麻烦。

这将是你的Person类：

class Person {
    String name;
    int age;
}

Answer 2

public static void highestAge(String[] names, int[] ages)
{
    //SET SENSIBLE DEFAULTS TO oldest AND index
    int index = 0;
    int oldest = ages[0];
    //Looping based on index
    for (int i = 0;  i < ages.length; i++)
    {
        if (ages[i] > oldest)
        {
           index = i;
           oldest = ages[i];
        }
}
System.out.print("Person " + names[index] + " has the highest age: " + ages[index] );
}//end of Size method

Answer 3

你离我不远。您需要维护一个最老的“索引”，然后您可以使用它来引用两个数组。

public static void highestAge (String[] names, int[] ages)
{
    String name
    int oldest = 0;
    int oldestIndex = -1;
    for (int index = 0; index < ages.length; index++) 
    {
        if (ages[index] > oldest)
        {
            oldest = number;
            oldestIndex = index;
        }
    }
    System.out.print("Person " + names[oldestIndex] + " has the highest age: " + oldest );
}//end of Size method

另外，我不知道你的例子是如何编译的，我没有看到数组highestAge在哪里声明：P

就个人而言，我会创建一个Person类，其名称和年龄为字段......

public class Person {
    private String name;
    private int age;
    public Person(String name, int age) {
        this.name = name;
        this.age = age;
    }

    public String getName() {
        return name;
    }

    public int getAge() {
        return age;
    }
}

然后我会在循环的每次迭代中创建一个新的Person并将它们添加到一组人（Person[] people = new Person[...]）中（实际上，我会使用{{1}的实现但那就是我）

你突然为你开辟了很多创造力。

您可以提供java.util.list方法来将人们进行比较。

isOlderThen(Person person)

您实际上只是根据每个人的年龄对数组进行排序，使用Arrays.sort和Comparator

Answer 4

1）创建一个类

class person
{
   String name;
   int    age;
}

2）只创建一个数组：Person []人

3）重写方法highestAge

Person getOldest( Person[] persons )
{
   Person oldest = null;
   for( Person person : persons )
   {
      if( oldest == null || person.age > oldest.age )
      {
         oldest = person;
      }
   }
   return oldest;
}

我如何匹配两个并行数组的索引？

4 个答案: