Question

我基本上有一个输入系统，人们输入数据，数据以特定的顺序打印在HTML表格中。

我有一些代码在下面工作正常，除了每次更新行时，编辑表而不是添加带有数据的新表。当我刷新数据消失时？

我的代码如下：

     $query = "SELECT * FROM rumours";
        $query = mysql_query($query) or die('MySQL Query Error: ' . mysql_error( $connect ));
        while ($row = mysql_fetch_assoc($query)) {
                        $id = $row['id'];
                        $band = $row['band'];
                        $title = $row['Title'];
                        $description = $row['description'];
                         }
$sql="INSERT INTO rumours (band, Title, description)
VALUES
('$_POST[firstname]','$_POST[lastname]','$_POST[age]')";

if (!mysql_query($sql,$connect))
  {
  die('Error: ' . mysql_error());
  }
 if (mysql_query($sql, $connect)) {
echo "<table border='1'>";
echo "<tr>";
echo "<td> $title  </td>";
echo "</tr>";
echo "<tr>";
echo "<td class = 'td1'> $description </td>";
echo "</tr>";
echo "</table>";
    }
echo "1 record added";

mysql_close($connect);

Answer 1

您只是从 inserted db行生成表，而不是db表中的所有db行。为此，您还需要echo每个找到的行的表代码：

$query = "SELECT * FROM rumours";
$query = mysql_query($query) or die('MySQL Query Error: ' . mysql_error( $connect ));
while ($row = mysql_fetch_assoc($query)) {
  $id = $row['id'];
  $band = $row['band'];
  $title = $row['Title'];
  $description = $row['description'];
  echo "<table border='1'>";
  echo "<tr>";
  echo "<td> $title  </td>";
  echo "</tr>";
  echo "<tr>";
  echo "<td class = 'td1'> $description </td>";
  echo "</tr>";
  echo "</table>";
}
$sql="INSERT INTO rumours (band, Title, description)
VALUES
('$_POST[firstname]','$_POST[lastname]','$_POST[age]')";
/* ... Code truncated to save space */

每次更新行时添加一个额外的表

1 个答案: