Question

这里我尝试使用管道创建一个简单的客户端和服务器。我分叉一个进程，让孩子充当客户端，父亲充当服务器。以下是代码：

#include<unistd.h>
#include<stdlib.h>
#include<stdio.h>
#include<string.h>

void errorMsg(char* msg)
{
    printf("\n%s\n", msg);
//  exit(0);
}

int main()
{
    int servfd[2];
    int clntfd[2];
    int chldpid;    

    if(pipe(servfd) < 0)
        errorMsg("Unable to create server pipe.!!");
    if(pipe(clntfd) < 0)
        errorMsg("Unable to create client pipe.!!!");

    if((chldpid = fork()) == 0)
    {
        char* txt = (char*) calloc(256, sizeof(char));
        close(servfd[1]);
        close(clntfd[0]);
        printf("@Client: Enter a string: ");
        //scanf("%s", txt);  //or fgets
        printf("Entered.!!");
        int n;
        txt = "Anything that you want will not be considered no matter what you do!!";
        char txt1[256];
        write(clntfd[1], txt, 256);

        //if(txt1[strlen(txt1) - 1] = '\n')
        //{ printf("asdasdas");
        //txt[strlen(txt) - 1] = '\0';}

        //int i = 0;
        //for(i = 0; i < 256; i++)
            //printf("%c", txt1[i]);

    while((n = read(servfd[0], txt1, 256)) > 0)
                    printf("\nAt client: %d bytes read\n\tString: %s\n", n, txt1);
}
    else    
    {
        //printf("Parent:   \n\n");
        close(servfd[0]);
        close(clntfd[1]);
        char* txt = NULL;
        int n, n1;  
        n = read(clntfd[0], &txt, 256);
        printf("Server read: %d", n);
        n1 = write(servfd[1], &txt, 256);
        printf("Server write: %d", n1);
        wait(chldpid);
    }
    exit(0);            
}

问题1：

这就是发生的事情。当我运行该程序时，它只打印Anything that yo（恰好是16个字符），而不是其他内容。当我试图使用评论中显示的txt1循环查看for的完整内容时，我发现在yo txt1之后有{null}值（天知道从哪里开始） }。之后它们应该是正常的内容。知道为什么会这样吗？

编辑：

当我尝试在适当的位置打印它们时，读取和写入的字节数都是正确的。它打印256 bytes read。但是，strlen的txt1大小为'16'。此外，程序在打印部分字符串后挂起。

问题2：

当我尝试使用注释中显示的scanf或fgets从用户处获取字符串时，程序会在我按下回车后立即终止。对于为什么会发生这种情况也没有任何线索。

对行为的任何见解都会有所帮助。很抱歉有多个问题。谢谢你的时间。！我正在使用ubuntu 12.04，如果这可能有任何帮助。

Answer 1

在您正在执行的父进程中：

char* txt = NULL;
.....  
n = read(clntfd[0], &txt, 256);

这是不正确的，因为您正在读取txt指向的缓冲区中的数据，但您没有分配缓冲区!!你所看到的是未定义行为的表现。

Answer 2

我在您的代码中添加了各种注释和更正。它现在按预期工作。您的主要问题是由codeaddict指出您没有分配缓冲区。我很惊讶你没有用SIGSEGV崩溃。

#include <unistd.h>
#include <stdlib.h>
#include <stdio.h>
#include <string.h>

void errorMsg(char* msg)
{
    printf("\n%s\n", msg);
//  exit(0);
}

// move this into global space and make it const (non modifiable, easyer to debug)
const char text_to_send[] = "Anything that you want will not be considered no matter what you do!!";

int main()
{
    int servfd[2];
    int clntfd[2];
    int chldpid;    

    if(pipe(servfd) < 0)
        errorMsg("Unable to create server pipe.!!");
    if(pipe(clntfd) < 0)
        errorMsg("Unable to create client pipe.!!!");

    if((chldpid = fork()) == 0)
    {
        char txt[256]; // You have to actually allocate a buffer (aka enough memory to hold your string. You have allocated a pointer to a buffer, but no actual buffer)
        close(servfd[1]);
        close(clntfd[0]);
        printf("@Client: Enter a string: ");

        scanf("%s", txt); // since you now actually have a buffer to put the input into this no longer fails

        printf("Entered.!!\n");
        int n;
        char txt1[256];
        write(clntfd[1], text_to_send, sizeof(text_to_send)); // write only as much as you actually have to say, not the whole size of your buffer

        while((n = read(servfd[0], txt1, 256)) > 0)
            printf("\nAt client: %d bytes read\n\tString: %s\n", n, txt1);

        // this is not nessesary at this point, but it is good style to clean up after yourself
        close(servfd[0]);
        close(clntfd[1]);
    }
    else    
    {
        //printf("Parent:   \n\n");
        close(servfd[0]);
        close(clntfd[1]);
        char txt[256]; // same here, you need to actually allocate a buffer.
        int n, n1;  
        n = read(clntfd[0], txt, 256); // read into txt, not &txt. you want to read into your buffer pointed to by txt, not into the part of memory that contains the pointer
        printf("Server read: %d\n", n);
        n1 = write(servfd[1], txt, n); // do not send the whole buffer, just as much as you have actually useful information in it
        printf("Server write: %d\n", n1);

        // close the loose file descriptors, else your child will read on them forever
        close(servfd[1]);
        close(clntfd[0]);

        int status;
        wait(&status); // this is called like this. if you want to use the pid you call waitpid(chldpid, &status, 0);
    }
    exit(0);            
}

在C中使用管道创建客户端和服务器时的奇怪行为

问题1：

编辑：

问题2：

2 个答案: