Question

我有如下数据库模式：

Teams(teamID,teamName,home,leagueName)
Games(gameID,homeTeamID,guestTeamID,date)

如何查询（使用SQL）所有teamID s团队对阵球队1而不是对阵球队2。 'team1和team2是teamName列中的一些数据值？

Answer 1

假设没有HomeTeam或GuestTeam的游戏。试试这个，

SELECT  a.gameID,
        b.TeamName AS HomeTeam,
        c.TeamName AS GuestTeam,
        a.`date`
FROM    GAMES a
        INNER JOIN Teams b
            ON a.homeTeamID = b.teamID
        INNER JOIN Teams c
            ON a.guestTeamID = c.teamID
WHERE   (
            b.TeamName = 'Team1' AND
            c.teamName <> 'Team2'
        )
        OR
        (
            c.TeamName = 'Team1' AND
            b.teamName <> 'Team2'
        )

Answer 2

球队对阵球队1但不反对的所有球队ID team2

SELECT t1.teamName AS 'Home', t2.TeamName AS 'Guest', g.Date
FROM
(
   SELECT *
   FROM Games
   WHERE (homeTeamID  = 'Team 1' OR guestTeamID  =  'Team 1')
     AND (homeTeamID <> 'Team 2' OR guestTeamID <> 'Team 1')
) g ON t.teamID = hg.homeTeamID
INNER JOIN teams t1 ON g.homeTeamID  = t1.teamId 
INNER JOIN teams t2 ON g.guestTeamID = t2.teamId

如何使用以下架构编写此查询？

2 个答案: