Question

我有运行时读入的xml文件，是否可以在运行时针对xsd文件验证xml？使用c＃

Answer 1

试试这个：

public void ValidateXmlDocument(
    XmlReader documentToValidate, string schemaPath)
{
    XmlSchema schema;
    using (var schemaReader = XmlReader.Create(schemaPath))
    {
        schema = XmlSchema.Read(schemaReader, ValidationEventHandler);
    }

    var schemas = new XmlSchemaSet();
    schemas.Add(schema);

    var settings = new XmlReaderSettings();
    settings.ValidationType = ValidationType.Schema;
    settings.Schemas = schemas;
    settings.ValidationFlags =
        XmlSchemaValidationFlags.ProcessIdentityConstraints |
        XmlSchemaValidationFlags.ReportValidationWarnings;
    settings.ValidationEventHandler += ValidationEventHandler;

    using (var validationReader = XmlReader.Create(documentToValidate, settings))
    {
        while (validationReader.Read())
        {
        }
    }
}

private static void ValidationEventHandler(
    object sender, ValidationEventArgs args)
{
    if (args.Severity == XmlSeverityType.Error)
    {
        throw args.Exception;
    }

    Debug.WriteLine(args.Message);
}

Answer 2

我的代码太多了！我在测试中使用它：

    public static bool IsValid(XElement element, params string[] schemas)
    {
        XmlSchemaSet xsd = new XmlSchemaSet();
        XmlReader xr = null;
        foreach (string s in schemas)
        { // eh, leak 'em. 
            xr = XmlReader.Create(
                new MemoryStream(Encoding.Default.GetBytes(s)));
            xsd.Add(null, xr);
        }
        XDocument doc = new XDocument(element);
        var errored = false;
        doc.Validate(xsd, (o, e) => errored = true);
        if (errored)
            return false;

        // If this doesn't fail, there's an issue with the XSD.
        XNamespace xn = XNamespace.Get(
                      element.GetDefaultNamespace().NamespaceName);
        XElement fail = new XElement(xn + "omgwtflolj/k");
        fail.SetAttributeValue("xmlns", xn.NamespaceName);
        doc = new XDocument(fail);
        var fired = false;
        doc.Validate(xsd, (o, e) => fired = true);
        return fired;
    }

这个将模式作为字符串（程序集中的文件资源）接收，并将它们添加到模式集中。我验证，如果它无效，我返回false。

如果发现xml无效，我会进行否定检查以确保我的模式没有搞砸。它不能保证万无一失，但我用它来查找我的模式中的错误。

Answer 3

更简单的解决方案..

        try
        {
            XmlReaderSettings Xsettings = new XmlReaderSettings();
            Xsettings.Schemas.Add(null, "personDivideSchema.xsd");
            Xsettings.ValidationType = ValidationType.Schema;

            XmlDocument document = new XmlDocument();
            document.Load("person.xml");

            XmlReader reader = XmlReader.Create(new StringReader(document.InnerXml), Xsettings);


            while (reader.Read());
        }
        catch (Exception e)
        {
            Console.WriteLine(e.Message.ToString());
        }

Answer 4

希望此链接有所帮助：

Validation of XML with XSD

可以在运行时使用代码对xsd验证xml吗？

4 个答案: