Question

我想在这里做一些非常简单的事情。我想要做的就是在MySQL中插入信息以下是表单的代码。

 <?php
 $host=""; // Host name 
 $username=""; // Mysql username 
 $password=""; // Mysql password 
 $db_name=""; // Database name 
 $tbl_name=""; // Table name 

 // Connect to server and select database.
 mysql_connect("$host", "$username", "$password")or die("cannot connect"); 
 mysql_select_db("$db_name")or die("cannot select DB");

 // get value of id that sent from address bar
 $dj=$_GET['dj'];

 // Retrieve data from database 
 $sql="SELECT * FROM $tbl_name WHERE dj='$dj'";
 $result=mysql_query($sql);
 $rows=mysql_fetch_array($result);
 ?>

<table width="400" border="0" cellspacing="1" cellpadding="0">
<tr>
<form name="form1" method="post" action="insert_ac.php">
<td>
<table width="100%" border="0" cellspacing="1" cellpadding="0">
<tr>
<td>&nbsp;</td>
<td colspan="3"><strong>Insert The information for the Now PlayingProgram.</strong>
</td>
</tr>
<tr>
<td align="center">&nbsp;</td>
<td align="center">&nbsp;</td>
<td align="center">&nbsp;</td>
<td align="center">&nbsp;</td>
</tr>
<tr>
<td align="center">&nbsp;</td>
<td align="center"><strong>Name</strong></td>
<td align="center"><strong>Email</strong></td>
<td align="center"><strong>Email2</strong></td>
</tr>
<tr>
<td>&nbsp;</td>
<td align="center">
<input name="name" type="text" id="name" value="">
</td>
<td align="center">
<input name="email" type="text" id="email" value="" size="15">
</td>
<td>
<input name="email2" type="text" id="email2" value="" size="15">
</td>
</tr>
<tr>
<td align="center">&nbsp;</td>
<td align="center"><strong>Twitter</strong></td>
<td align="center"><strong>Twitter2</strong></td>
<td align="center"><strong>Avatar</strong></td>
</tr>
<tr>
<td>&nbsp;</td>
<td align="center">
<input name="twitter" type="text" id="twitter" value="">
</td>
<td align="center">
<input name="twitter2" type="text" id="twitter2" value="" size="15">
</td>
<td>
<input name="avatar" type="text" id="avatar" value="" size="15">
</td>
</tr>
<tr>
<td align="center">&nbsp;</td>
<td align="center"><strong>Facebook</strong></td>
<td align="center"><strong>Facebook2</strong></td>
<td align="center"><strong>Type</strong></td>
</tr>
<tr>
<td>&nbsp;</td>
<td align="center">
<input name="facebook" type="text" id="facebook" value="">
</td>
<td align="center">
<input name="facebook2" type="text" id="facebook2" value="" size="15">
</td>
<td>
<input name="type" type="text" id="type" value="" size="15">
</td>
</tr>
<tr>
<td align="center">&nbsp;</td>
<td align="center"><strong>Alias1</strong></td>
<td align="center"><strong>Alias2</strong></td>
<td align="center"><strong>Alias3</strong></td>
</tr>
<tr>
<td>&nbsp;</td>
<td align="center">
<input name="alias1" type="text" id="alias1" value="">
</td>
<td align="center">
<input name="alias2" type="text" id="alias2" value="" size="15">
</td>
<td>
<input name="alias3" type="text" id="alias3" value="" size="15">
</td>
</tr>

<tr>
<td align="center">&nbsp;</td>
 <td colspan="3" align="center"><strong>Request Line</strong></td>
</tr>
<tr>
<td>&nbsp;</td>
<td colspan="3" align="center">
 <input name="address" type="text" id="address" value="" size="65">
 </td>
 </tr>
 <tr>
 <td>&nbsp;</td>
 <td>
 <input name="dj" type="hidden" id="dj" value="">
 </td>
 <td align="center">
 <input type="submit" name="Submit" value="Submit">
 </td>
 <td>&nbsp;</td>
 </tr>
 </table>
 </td>
 </form>
 </tr>
 </table>
  <?php
 // close connection 
 mysql_close();
 ?>

现在我想要做的是将信息插入我在此表单中输入的数据库中。好吧，我的问题是，当我输入一些数据并点击提交时，我得到的只是错误。

让我们来看看我的incert_ac.php 代码如下：

<?php
 $host=""; // Host name 
 $username=""; // Mysql username 
 $password=""; // Mysql password 
 $db_name=""; // Database name 
 $tbl_name=""; // Table name 

 // Connect to server and select database.
 mysql_connect("$host", "$username", "$password")or die("cannot connect"); 
 mysql_select_db("$db_name")or die("cannot select DB");

 // Connect to server and select database.
 mysql_connect("$host", "$username", "$password")or die("cannot connect"); 
 mysql_select_db("$db_name")or die("cannot select DB");

 // insert data in mysql database 
 $sql="INSERT INTO $tbl_name (name, email, email2, twitter, twitter2, avatar, facebook, facebook2, type, alias1, alias2, alias3, address, dj)
  VALUES('{$_POST[name]}', '{$_POST[email]}', '{$_POST[email2]}', '{$_POST[twitter]}', '{$_POST[twitter2]}', '{$_POST[avatar]}', '{$_POST[facebook]}', '{$_POST[facebook2]}', '{$_POST[type]}', '{$_POST[alias1]}', '{$_POST[alias2]}', '{$_POST[alias3]}', '{$_POST[address]}', '{$_POST[dj]}')";
 $result=mysql_query($sql);

 // if successfully inserted 
 if($result){
 echo "Successful";
 echo "<BR>";
 echo "<a href='list_records.php'>View result</a>";
 echo "1 record added";
 }

 else {
echo "ERROR";
}

?>

我想知道我是否只是在这里有语法甚至是拼写问题！任何帮助将不胜感激。

Answer 1

列名name和type需要使用刻度标记，因为它们是MySQL中的保留名称。

将$sql=行更新为以下代码：

$sql = "INSERT INTO $tbl_name (`name`, email, email2, twitter, twitter2, avatar, facebook, facebook2, `type`, alias1, alias2, alias3, address, dj) VALUES (
    '".mysql_real_escape_string($_POST['name'])."',
    '".mysql_real_escape_string($_POST['email'])."',
    '".mysql_real_escape_string($_POST['email2'])."',
    '".mysql_real_escape_string($_POST['twitter'])."',
    '".mysql_real_escape_string($_POST['twitter2'])."',
    '".mysql_real_escape_string($_POST['avatar'])."',
    '".mysql_real_escape_string($_POST['facebook'])."',
    '".mysql_real_escape_string($_POST['facebook2'])."',
    '".mysql_real_escape_string($_POST['type'])."',
    '".mysql_real_escape_string($_POST['alias1'])."',
    '".mysql_real_escape_string($_POST['alias2'])."',
    '".mysql_real_escape_string($_POST['alias3'])."',
    '".mysql_real_escape_string($_POST['address'])."',
    '".mysql_real_escape_string($_POST['dj'])."')";

编辑：添加了一些SQL输入清理

INSERT INTO mysql数据库无法正常工作

1 个答案: