Question

我的JSON文件的一小部分如下所示。它传递了一个JSON验证器。（我添加了cl

{
"next_page": "?page=2&max_id=210389654296469504&q=cocaine&geocode=40.665572%2C-73.923557%2C10mi&rpp=100",
"completed_in": 0.289,
"max_id_str": "210389654296469504",
"since_id_str": "0",
"refresh_url": "?since_id=210389654296469504&q=cocaine&geocode=40.665572%2C-73.923557%2C10mi",
"results": [
    {
        "iso_language_code": "en",
        "to_user_id": 486935435,
        "to_user_id_str": "486935435",
        "profile_image_url_https": "https://si0.twimg.com/profile_images/1561856049/Zak_W_Photo_normal.jpg",
        "from_user_id_str": "82389940",
        "text": "@Bill__Murray cocaine &gt; productivity! Last night I solved the euro crisis and designed a new cat. If I could only find that napkin.",
        "from_user_name": "Zak Williams",
        "in_reply_to_status_id_str": "210319741322133504",
        "profile_image_url": "http://a0.twimg.com/profile_images/1561856049/Zak_W_Photo_normal.jpg",
        "id": 210389654296469500,
        "to_user": "Bill__Murray",
        "source": "&lt;a href=&quot;http://twitter.com/#!/download/iphone&quot; rel=&quot;nofollow&quot;&gt;Twitter for iPhone&lt;/a&gt;",
        "in_reply_to_status_id": 210319741322133500,
        "to_user_name": "Bill Murray",
        "location": "Brooklyn",
        "from_user": "zakwilliams",
        "from_user_id": 82389940,
        "metadata": {
            "result_type": "recent"
        },
        "geo": "null",
        "created_at": "Wed, 06 Jun 2012 15:16:17 +0000",
        "id_str": "210389654296469504"
    }
]
}

当我尝试通过键入以下代码在Python中加载它时，我收到以下错误。

代码

 import simplejson as json
 testname = 'test.txt'
 record = json.loads(testname)

错误

 raise JSONDecodeError("No JSON object could be decoded", s, idx)
 simplejson.decoder.JSONDecodeError: No JSON object could be decoded: line 1 column 0 (char 0)

我做错了什么？实际上，我使用simplejson.dump

生成了该文件

Answer 1

json.loads()函数从字符串加载JSON数据，而您只是给它一个文件名。字符串test.txt不是有效的JSON字符串。请尝试以下操作从文件加载JSON数据：

with open(testname) as f:
    record = json.load(f)

（如果您使用的旧版本的Python不支持with语句（可能是您使用旧版simplejson所指示的），那么您必须打开并自己关闭文件。）

使用simplejson从Python解码来自Twitter的JSON文件

1 个答案: