Question

目前我无法从给定数组中删除重复项。我编写了一个程序，但它只返回所有零。我不能使用hashset。

public class Assignment05a 
{
    public static void main(String args[]) 
    {
         int[] sourceArray = {1,4,5,4,1,2,3,5,9,7,12,-5,1,4,-1,-5,12,1};
         java.util.Arrays.sort(sourceArray);
         eliminateDuplicates(sourceArray); 
    }

    public static int[] eliminateDuplicates(int[] list)
    {   
         int[] noDup = new int[list.length]; 

         for (int c = 0; c < list.length-1; c++)
         {
             if (list[c] != list[c+1])
                {
                    list[c] = noDup[c];
                }
         }

         for(int i = 0; i < noDup.length; i++)
         {
             System.out.println(noDup[i]);
         }
         return noDup;
}   
}

Answer 1

我想我们可以更新eliminateDuplicates方法，如下所示：

public static int[] eliminateDuplicates(int[] list){   
     List<Integer> noDup = new ArrayList<Integer>(); 
     noDup.add(list[0]);
     for (int c = 1; c < list.length-1; c++){
         if(!noDup.contains(list[c])){
             noDup.add(list[c]); 
         }
     }
     int[] noDupArray = new int[noDup.size()];
     for(int i = 0; i < noDup.size(); i++){
         noDupArray[i] = noDup.get(i);
         System.out.println(noDup.get(i));
     } 
     return noDupArray;
}

如果您不想使用List/ArrayList，我相信您可以更新eliminateDuplicates方法，如下所示：

public static int[] eliminateDuplicates(int[] list){   
     int[] noDup = new int[list.length]; 
     noDup[0] = list[0];
     int noDupCount = 1;
     for (int c = 1; c < list.length-1; c++){
         boolean bAlreadyAdded = false;
         for (int d = 0; d < noDup.length-1; d++){
           if (noDup[d] == list[c]){
               bAlreadyAdded = true;
            }
         }
         if(!bAlreadyAdded){
             noDup[noDupCount++] = list[c]; 
         }
     }
     int[] newUniques = new int[noDupCount];
     for(int i = 0; i < noDupCount; i++){
         newUniques[i] = noDup[i];
         System.out.println(noDup[i]);
     }
     return newUniques;
}

Answer 2

您可以将每个字符映射到布尔数组，并根据布尔数组索引中该字符的ascii值将其设置为true或false。看看这个：

在java中从数组中删除重复项不能使用hashset

2 个答案: