Question

我是C＃编程和XML的新手。我想用日期（我将从日期选择器中选择）更改字符串（以@开头并以'开头），请查看下面的XML文件

<steps>
  <step1>drop table emp1 purge</step1> 
  <step2>create table emp1 as select e1.first_name ,e1.last_name ,e1.phone_number ,e1.salary     ,e1.hire_date from employees e1 where e1.hire_date between '@m_start_date' to '@m_end_date' group by e1.first_name ,e1.last_name ,e1.phone_number ,e1.salary ,e1.hire_date</step2> 
  <step3>select * from emp1</step3> 
</steps>

在上面的Xml代码中，我想用'01 -sep-2012'更改@m_start_date，用'30 -sep-2012更改@m_end_date'最重要的一点是字符串@m_start_date和@m_end_date没有修复它我的更改其他xml文件（即它可能是@wk_start_dte和wk_end_dte）所以我需要一个C＃中的逻辑，我们可以找到一个以@开头的字符串并以'结尾'，所以我们可以用日期替换这个字符串。

预期结果应该是这样的

<steps>
  <step1>drop table emp1 purge</step1> 
  <step2>create table emp1 as select e1.first_name ,e1.last_name ,e1.phone_number ,e1.salary     ,e1.hire_date from employees e1 where e1.hire_date between '01-sep-2012' to '30-sep-2012' group by e1.first_name ,e1.last_name ,e1.phone_number ,e1.salary ,e1.hire_date</step2> 
  <step3>select * from emp1</step3> 
</steps>

你能帮助我在C＃中获得这个逻辑吗？

Answer 1

假设您的XML位于名为test的字符串中：

test = System.Text.RegularExpressions
             .Regex.Replace(test, "'[^']*start[^']*'", "'01-sep-2012'");

test = System.Text.RegularExpressions
             .Regex.Replace(test, "'[^']*end[^']*'", "'30-sep-2012'");

Answer 2

除了Ivan关于文本替换的答案之外，您可能需要执行以下操作才能找到节点

XmlDocument xDoc = new XmlDocument();
xDoc.Load("yourXml.XML");

XmlNode nodetoChange = xDoc.DocumentElement.SelectSingleNode("step2");

string xmlValue = nodetoChange.InnerText;

//Now apply Ivan's logic to replace text as you wish so that xmlValue new text
//then continue to save xml as shown below.

nodetoChange.InnterText = xmlValue;

xDoc.Save(); //In case you need to save it on hard-disk.
xDoc = null;

希望有所帮助，谢谢 Milind

使用C＃将字符串替换为XML中的日期

2 个答案: