Question

我有一个像以下的mysql表：

id, visitorid, pageid

当访问者访问网站时，它会将访问者ID和页面ID存储为一行。

我正在尝试将访问网站的访问者数量提取X次。（图表）。所以有多少人只访问一页，有多少人访问2页......

到目前为止，我有：

SELECT COUNT(visid),visid FROM vislog GROUP BY visid ORDER BY COUNT(visid) DESC

但我不知道如何计算计数的下一部分。

可以作为mysql查询吗？

编辑： 我有added my answer。

Answer 1

您可以将查询包装在另一个中：

SELECT
    cnt      AS page_visits
  , COUNT(*) AS number_of_visitors
FROM
    ( SELECT 
          COUNT(*) AS cnt                --- use: COUNT(DISTINCT page_id)
                                         --- for a different count
      FROM vislog 
      GROUP BY visid
   ) AS grp
GROUP BY cnt 
ORDER BY number_of_visitors ;

或（我认为这对于将数字传递给图表更有意义），删除与放置相同的ORDER BY：

ORDER BY cnt ;

Answer 2

一种方法是将此查询包装到另一个中：

SELECT COUNT(visid) FROM (
    SELECT COUNT(visid) AS cvisid, visid 
      FROM vislog 
  GROUP BY visid 
  HAVING cvisid = 2) AS c

但我认为您需要获取访问的直方图：这可以通过PHP完成（假设查询与问题中的查询相同）：

$results = array();
// query preparation skipped, as it's obviously done by the OP himself
while ($row = $sth->fetch()) {
  $count = $row['cvisid'];
  if (isset($results[$count])) {
    $results[$count]++;
  }
  else {
    $results[$count] = 1;
  }
}

或者使用MySQL本身：

SELECT cvisid, 
       COUNT(cvisid) AS cnt 
  FROM (
    SELECT visid,
           COUNT(visid) AS cvisid 
      FROM vislog 
  GROUP BY visid ) AS c
GROUP BY cvisid

Answer 3

尝试使用以下查询

SELECT COUNT(a.page_visits) AS no_of_visitors, a.page_visits AS page_count
FROM(
SELECT COUNT(DISTINCT pageid) AS page_visits
FROM vislog
GROUP BY visid) AS a
GROUP BY a.page_visits;

希望它有所帮助...

Answer 4

Raina77ow（第二个回复）在他的第三个代码块中返回了一个干净的解决方案

    SELECT cvisid, 
           COUNT(cvisid) AS cnt 
      FROM (
        SELECT visid,
               COUNT(visid) AS cvisid 
          FROM vislog 
      GROUP BY visid ) AS c
    GROUP BY cvisid

谢谢

Answer 5

我可以这样解决：

SELECT cnt, COUNT(cnt) FROM (
    SELECT COUNT(visid) as cnt FROM vislog GROUP BY visid
) x GROUP BY cnt ORDER BY cnt ASC

小x很重要。

MYSQL计数？

5 个答案: