我有多个JSON文件，我想解析，编辑和合并到一个对象，最终将重新编码并输出为单个JSON。
我目前有一个工作示例，当我解析和编辑一个对象时，但我无法弄清楚如何做两个并得到一个结果。
工作示例：
$source = 'http://www.jakedup.com/_/source1';
$data = json_decode(file_get_contents($source));
// THIS WILL BE THE FINAL OUTPUT OBJECT
$output = new stdClass();
// GET THE ARTICLE DATES AS AN ARRAY
$tracks = get_object_vars($data->tracks);
// LOOPS OVER ARTICLE PUBDATES TO GET THE OUTER OBJECTS
foreach ($tracks as $key=>$val) {
// LOOPS OVER THE INNER OBJECTS IN EACH ARTICLE PUBDATE
foreach ($data->tracks->$key as $object) {
// ADD IT ONTO THE OUTPUT OBJECT WITH "ID" AS PARENT NAME
$output->{$object->id} = $object;
}
}
echo json_encode($output);
以下是我的JSON示例。我提供了两个示例，但我正在寻找一种动态合并无限数量的JSON文件的方法。
JSON Source1：
{
"foo":"bar",
"tracks":{
"1349496000":[
{
"id":"25328",
"is_promo":null,
"is_feature":null,
"listens":"1312",
"downloads":"777"
},
{
"id":"25327",
"is_promo":null,
"is_feature":null,
"listens":"1255",
"downloads":"578"
},
{
"id":"25329",
"is_promo":null,
"is_feature":null,
"listens":"341",
"downloads":"139"
}
],
"1349323200":[
{
"id":"25310",
"is_promo":null,
"is_feature":null,
"listens":"10793",
"downloads":"4953"
}
]
}
}
JSON来源2：
{
"foo":"bar",
"tracks":{
"1349323200":[
{
"id":"25303",
"is_promo":null,
"is_feature":null,
"listens":"2347",
"downloads":"1499"
}
],
"1349236800":[
{
"id":"25266",
"is_promo":null,
"is_feature":null,
"listens":"24485",
"downloads":"19366"
}
]
}
}
我一直在寻找在循环中获取源代码的想法，但是当它合并数据时我被困住了。我所有的不同努力都没有产生正确的数据结构。
当前测试代码：
$source = 'http://www.jakedup.com/_/source';
$pages = 2;
for ($i = 1; $i <= $pages; $i++) {
$sources[$i] = $source.$i;
${'source'.$i} = json_decode(file_get_contents($source.$i));
}
我现在有两个对象 - $ source1＆amp; $ source2 - 但我不知道下一步该做什么。
这是我期待的输出：
{
"25328": {
"id": "25328",
"is_promo": null,
"is_feature": null,
"listens": "1312",
"downloads": "777",
"timestamp": "1349496000"
},
"25327": {
"id": "25327",
"is_promo": null,
"is_feature": null,
"listens": "1255",
"downloads": "578",
"timestamp": "1349496000"
},
"25329": {
"id": "25329",
"is_promo": null,
"is_feature": null,
"listens": "341",
"downloads": "139",
"timestamp": "1349496000"
},
"25310": {
"id": "25310",
"is_promo": null,
"is_feature": null,
"listens": "10793",
"downloads": "4953",
"timestamp": "1349323200"
},
"25303": {
"id": "25303",
"is_promo": null,
"is_feature": null,
"listens": "2347",
"downloads": "1499",
"timestamp": "1349323200"
},
"25266": {
"id": "25266",
"is_promo": null,
"is_feature": null,
"listens": "24485",
"downloads": "19366",
"timestamp": "1349236800"
}
}
提前感谢您的帮助！
答案 0 :(得分：4)
使用PHP数组更简单一点，而不是尝试使用数字属性构建stdClass对象。如果PHP数组具有非连续的非零键，json_encode()将自动生成对象{}而不是数组[]。同样，json_decode()有一个可选的第二个参数来生成关联数组而不是对象。因此，我建议将文件解码为数组并循环遍历它们，将每个id附加到输出数组上，最后再次json_encode()。
您的代码暗示您拥有“http://www.jakedup.com/_/source1”等JSON源文件。您处于正确的轨道上，但不是填充新的变量变量，而是在循环中检索和解码每个文件，并将其直接附加到输出数组。
// 5 source numbers, don't have to be consecutive
$sources = array(1,2,3,4,5);
// Output array to be encoded as JSON
$output = array();
// Loop over all the source files, retrieve them and add tracks onto the output
foreach ($sources as $sourcenum) {
$source = "http://www.jakedup.com/_/source$sourcenum";
$source_json = file_get_contents($source);
// Decode it as an associative array, passing TRUE as second param
$source_array = json_decode($source_json, TRUE);
// Now loop over the tracks (which are an array) and append each to the output
// the original key looks like a timestamp
foreach ($source_array['tracks'] as $timestamp => $ts) {
foreach ($ts as $track) {
// Add the track id to $output as a key
// This doesn't check if the id already exists...
// if it does, it will just be overwritten with this one
$output[$track['id']] = $track;
// Optionally, save the original timestamp key into the track array
// Maybe you don't care about this
$output[$track['id']]['timestamp'] = $timestamp;
}
}
}
// Look over your array
var_dump($output);
// Finally, re-encode the whole thing back to JSON
// using JSON_FORCE_OBJECT (even though it shouldn't be necessary)
$output_json = json_encode($output, JSON_FORCE_OBJECT);
{
"25328": {
"id": "25328",
"is_promo": null,
"is_feature": null,
"listens": "1312",
"downloads": "777",
"timestamp": 1349496000
},
"25327": {
"id": "25327",
"is_promo": null,
"is_feature": null,
"listens": "1255",
"downloads": "578",
"timestamp": 1349496000
},
"25329": {
"id": "25329",
"is_promo": null,
"is_feature": null,
"listens": "341",
"downloads": "139",
"timestamp": 1349496000
},
"25310": {
"id": "25310",
"is_promo": null,
"is_feature": null,
"listens": "10793",
"downloads": "4953",
"timestamp": 1349323200
},
"25303": {
"id": "25303",
"is_promo": null,
"is_feature": null,
"listens": "2347",
"downloads": "1499",
"timestamp": 1349323200
},
"25266": {
"id": "25266",
"is_promo": null,
"is_feature": null,
"listens": "24485",
"downloads": "19366",
"timestamp": 1349236800
}
}