Question

products purchased
--------------------------
bana
bana
bana
stra
kiwi

reward requirements table (related to a rewards table)
reward id, products
----------------------
1,bana
1,bana
1,bana
2,stra
2,bana
3,stra
4,cart
5,bana
5,bana
5,oliv

你能帮我用sql来获得奖励吗？购买的产品符合资格？

在上述情况下，奖励ID将是：

1
2
3

如果有更好的设计可以使解决方案更容易，我也欢迎这些。我希望，为了便于解释，我正在使用产品名称。（我稍后会用产品ID替换）

Answer 1

此查询将解决您的问题。

select r.reward_id
from (
  select reward_id, product, count(*) needed
  from reward_requirements
  group by reward_id, product
) r
left join (
  select product, count(*) bought
  from products_purchased
  group by product 
) p on r.product=p.product and p.bought >= r.needed
group by r.reward_id
having count(reward_id) = count(distinct p.product)
order by r.reward_id

为了使您的设计更好，您可以重做reward_requirements以获得列（产品，需要），而不必多次列出它。它也将摆脱第一个子查询。

Answer 2

使用此架构：

CREATE TABLE            product
(
    product_id          int IDENTITY
    , name              varchar(50)
)

CREATE TABLE            requirement
(
    requirement_id      int IDENTITY
    , product_id        int
    , quantity          int
    , reward_id         int
)

CREATE TABLE            reward
(
    reward_id           int IDENTITY
    , reward            varchar(50)
)

CREATE TABLE            purchased
(
    purchased_id        int IDENTITY
    , product_id        int
    , quantity          int
)

您的查询变为：

SELECT      requirement.reward_id
FROM        requirement
            LEFT JOIN purchased
                ON  purchased.product_id = requirement.product_id
                AND purchased.quantity >= requirement.quantity
GROUP BY    requirement.reward_id
HAVING      COUNT(purchased.product_id) = COUNT(requirement.reward_id);

这是一个可以使用的SQLFiddle：http://sqlfiddle.com/#!3/e93c9/7

奖励产品符合条件

2 个答案: