Question

以下代码构建没有错误，但是当我运行程序时，接收的数据不会显示在输出中。当我在myReceivedLines = port.ReadExisting();上放置一个断点时，我得到了：

System.InvalidOperationException。

在程序本身，重新启动计算机后，它说：

Access to COM5 is denied

我该怎么做才能解决这个问题？

代码：

//Fields
SerialPort port;
string myReceivedLines;

   protected override void SolveInstance(IGH_DataAccess DA)
  {

    List<string> gcode = new List<string>();
    DA.GetDataList(0, gcode);
    string selectedportname = default(string);
    DA.GetData(1, ref selectedportname);
    int selectedbaudrate = default(int);
    DA.GetData(2, ref selectedbaudrate);
    bool connecttodevice=default(bool);
    DA.GetData(3, ref connecttodevice);
    bool sendtoprint= default(bool);
    DA.GetData(4, ref sendtoprint);


    if (!DA.GetDataList(0, gcode)) return;
    if (!DA.GetData(1, ref selectedportname)) return;
    if (!DA.GetData(2, ref selectedbaudrate)) return;
    if (!DA.GetData(3, ref connecttodevice)) return;
    if (!DA.GetData(4, ref sendtoprint)) return;


    port = new SerialPort(selectedportname, selectedbaudrate, Parity.None, 8, StopBits.One); //Create the serial port
    port.DtrEnable = true;   //enables the Data Terminal Ready (DTR) signal during serial communication (Handshaking)
    port.Open();             //Open the port
    port.DataReceived += this.portdatareceived;


    if (gcode == null)
    {
        AddRuntimeMessage(GH_RuntimeMessageLevel.Warning, "Specify a valid GCode");
        return;
    }

    if (connecttodevice == true)
    {
        DA.SetDataList(0, myReceivedLines);
    }

        if (sendtoprint == true)
        {
            foreach (String s in gcode)
            {
                port.WriteLine(s);
            }
        }

              }


    //subscriber method for the port.DataReceived Event
    private void portdatareceived(object sender, System.IO.Ports.SerialDataReceivedEventArgs e)
    {
            myReceivedLines = port.ReadExisting();
    }

Answer 1

SerialPort的DataReceived事件在与UI线程不同的线程上运行。您需要执行类似DataReceived事件建议的MSDN页面。您获得访问被拒绝错误的原因是因为端口仍处于打开状态，重新启动计算机以正确重新启动程序是不够的。

即。来自上面的链接

private static void DataReceivedHandler( object sender, SerialDataReceivedEventArgs e)
{
    SerialPort sp = (SerialPort)sender;
    string indata = sp.ReadExisting();
}

SerialPort.ReadExisting方法不显示接收的数据

1 个答案: