Question

想象一下，我有一个名为uselessKeywords的数组。它的值为“and”，“but”，“the”。

如果我还有一个字符串，其中包含“cool，and，but，and”，如何判断数组中的任何值在字符串中的次数？

Answer 1

这样做会有所作为，但您必须注意误报，例如andover和thesaurus。

$uselesskeywords = array('and', 'but', 'the');
$regex = implode('|', $uselesskeywords);
$count = count(preg_grep("/($regex)/", "cool,and,but,and"));

Answer 2

你可以使用foreach uselessKeywords

遍历字符串

$count = 0;
foreach($uselessKeywords as $needle){
    $count = $count + substr_count($str, $needle);
}

echo $count;

Answer 3

改进Marc B（添加一些逗号以消除误报andover和thesaurus;我添加了前瞻，因为某些值可以逐个显示）：

$uselesskeywords = array('and', 'but', 'the');
$str = "cool,and,but,and";
$regex = implode('(?=,)|,', $uselesskeywords);
$count = count(preg_grep("/,$regex(?=,)/", ",$str,"));

Answer 4

试试这个..

<?php
function uselessKeywordOccurances ($myString, $theArray) {
    $occurances = array();
    $myTestWords = preg_split("/,/", $myString);
    for($i = 0; $i < count($myTestWords); $i++)     {
        $testWord = $myTestWords[$i];
        if (in_array($testWord, $theArray)) {
            array_push($occurances, $testWord);
        }
    }   
    $grouped = array_count_values($occurances);
    arsort($grouped);
    return $grouped;
}

$uselessKeywords = array("and", "but", "the");
$testWords = "cool,and,but,and,and,the,but,wonderful";
$result = uselessKeywordOccurances($testWords, $uselessKeywords);
var_dump($result);
?>

它应该返回uselessKeywords的出现，就像这样..

array(3) { ["and"]=> int(3) ["but"]=> int(2) ["the"]=> int(1) }

如何判断数组中的值在字符串中的次数

4 个答案: