如何在用户点击不同按钮时从主jframe类调用/显示这些不同的jpanel? 如果我有40-50个这样的jpanel,那么从主类中切换这些面板的最有效方法是什么呢?
答案 0 :(得分:4)
这是一个非常简单的示例,它使用next()
和一个按钮来更改面板。
import java.awt.EventQueue;
import javax.swing.JFrame;
import javax.swing.JPanel;
import java.awt.CardLayout;
import java.awt.Color;
import java.awt.GridBagLayout;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import javax.swing.BorderFactory;
import javax.swing.BoxLayout;
import javax.swing.JButton;
import javax.swing.JLabel;
import javax.swing.border.Border;
public class TestCards extends JFrame {
private final CardLayout cl = new CardLayout();
private final JPanel cards = new JPanel(cl);
private final Border border = BorderFactory.createEmptyBorder(60, 60, 60, 60);
public TestCards() {
JPanel contentPane = new JPanel();
contentPane.setLayout(new BoxLayout(contentPane, BoxLayout.Y_AXIS));
contentPane.setBorder(BorderFactory.createEmptyBorder(5, 5, 5, 5));
setContentPane(contentPane);
JPanel panel1 = new JPanel(new GridBagLayout());
panel1.setBorder(border);
panel1.setBackground(Color.RED);
panel1.add(new JLabel("Card 1"));
cards.add(panel1, "First Panel");
JPanel panel2 = new JPanel(new GridBagLayout());
panel2.setBorder(border);
panel2.setBackground(Color.GREEN);
panel2.add(new JLabel("Card 2"));
cards.add(panel2, "Second Panel");
JPanel panel3 = new JPanel(new GridBagLayout());
panel3.setBorder(border);
panel3.setBackground(Color.BLUE);
panel3.add(new JLabel("Card 3"));
cards.add(panel3, "Third Panel");
JButton controlButton = new JButton("Switch");
controlButton.addActionListener(new ActionListener() {
@Override
public void actionPerformed(ActionEvent e) {
cl.next(cards);
}
});
JPanel controlPanel = new JPanel();
controlPanel.setBackground(Color.LIGHT_GRAY);
controlPanel.add(controlButton);
contentPane.add(cards);
contentPane.add(controlPanel);
cl.show(cards, "First Panel");
}
public static void main(String[] args) {
EventQueue.invokeLater(new Runnable() {
public void run() {
TestCards frame = new TestCards();
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
frame.pack();
frame.setLocationRelativeTo(null);
frame.setVisible(true);
}
});
}
}
另一种选择(众多)可以使用3个按钮,每个按钮显示一个特定的面板(使用show
代替next
)。
有关详细信息,请参阅this。
答案 1 :(得分:3)
CardLayout的previous
和next
方法可用于向前导航&分别通过卡组件返回。为了更容易地连续导航组件,您可以将卡名称放在String
数组中:
private static final String[] CARD_NAMES = { "name_2996062106101", ... };
然后,要显示特定的cardIndex
,您只需使用:
CardLayout layout = (CardLayout) contentPane.getLayout();
layout.show(contentPane, CARD_NAMES[cardIndex]);
有关详情,请参阅 How to Use CardLayout 。